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At the center, for every particle of mass in the earth to attract you gravitationally,
there's an equal particle with the same mass, located at the same distance from
you in exactly the opposite direction, balancing out the force toward the first one.
All of this is a theoretically ideal case. It assumes that the earth is a perfect sphere,
with the same distribution of mass in every direction from the center. The real earth
is lumpy, oddly shaped, and bumpy, so the acceleration of gravity wouldn't be exactly
zero at the center.
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∙ 13y ago
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Where the gravitational field strength is maximum?
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
How g becomes zero at the centre of earth?
At the center of a sphere, for every dot of mass attracting you toward it, there'sanother dot of mass at exactly the same distance from you in exactly the oppositedirection, attracting you toward it and canceling out the first one.
What factor affects gravitational force?
a gravitational force is a force of attraction , which attracts the all organisms and things , it also attracts the things in space [universe for where the gravitational field is there] for suppose our earth is a planet which have gravity , a sun[star] have more gravity in solar system. Improved answer: Gravitational force on a body brings the weight of the body. This is given by the expression W = mg. m-the mass of the body. g-the acceleration due to gravity. When this g gets affected then gravitational force varies. g is affected by so many factors. i) the altitu. de as we go away from the centre of the earth, g decreases ii) The depth. As we go towards the centre of the earth once again g decreases iii) Due to rotation of the earth the centrifugal acceleration would decrease the value of g, the most along the equator. iv) g could be proved to be GM/R2. G the universal gravitational constant M-mass of the earth R- radius of the earth. Hence due to non even spherical shape of the earth g value varies v) if a body gets immersed in a liquid then the weight is affected by the buoyant force. So the weight is reduced.
What distance from centre of earth where value of g is half?
You haven't said 'half' of WHAT .I'll assume that you mean "half of what it is on the surface", andI shall now proceed to answer the question that I have invented:(x/earth radius)2 = 2x = (earth radius) times sqrt(2) =9,010 km (5,599 miles) from the center2,639 km (1,640 miles) from the surface(all rounded)
What is earth's gravitational strength?
The strength (or apparent strength) of Earth's gravity varies with latitude, altitude, and local topography and geology. The gravitational force is often assumed to act directly towards the centre of the Earth, but the direction varies slightly because the Earth is not a perfectly uniform sphere. -Earth's gravity, denoted by g, refers to the acceleration that the Earth imparts to objects on or near its surface. In SI units this acceleration is measured in m/s² (metres per second per second, equivalently written as m·s−2 or N/kg). It has an approximate value of 9.8 m/s², which means that, ignoring air resistance, the speed of an object falling freely near the Earth's surface increases by about 9.8 metres per second every second. This quantity is informally known as "little g" (contrasted with G, the gravitational constant, known as "big G"). -The precise strength of the Earth's gravity varies depending on location. The nominal "average" value at the Earth's surface, known as standard gravity is, by definition, 9.80665 m/s² (32.1740 ft/s²). This quantity is denoted variously as gn, ge (though this sometimes means the normal equatorial value on Earth, 9.78033 m/s²), g0, gee, or simply g (which is also used for the variable local value). The symbol g should not be confused with g, the abbreviation for gram (which is not italicized).
IS VALUE OF g at centre of the earth maximum?
No, at the center of the Earth, it would be zero. That's because the gravitation of different parts of the Earth, in different directions, would cancel.
What is the value of G at center of earth?
Zero.
What is the value of 'g' at center of earth?
Zero.
What is the value of 'g' if the earth stops rotating?
i think value of g becomes zero
What is the earth's gravity in terms of acceleration?
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
What will be the time period of a simple pendulum at the centre of Earth?
Gravitational acceleration increases ,as distance from the centre decreases g=GM/s2 where, G=gravitational constant(6.67by 10^-11) M=mass of any pulling body(earth) s=distance from centre Though not infinite for the earth(is infinite for black hole) but the value of 'g' and hence, gravity is very high at the centre of the earth(6000 km below us), so a pendulum will swing very very fast at centre and its time period will be nearly zero T2=4(3.142)2l/g ================================= The centre of the Earth is occupied by solid material. A pendulum could not swing at that location. Also at the very centre of the earth all the mass is uniformly outside your location - there is no effective down position, so if you created a void to swing the pendulum it would not swing.
Is gravitational acceleration is same at every point?
Of course not.It varies. Gravitatinal accelaration(g) indirectly propatinal to squared value of distance from centre of earth. g=GM/(R^2) G=universal gravitatinal constant M=mass of earth R=distance from centre
What is the acceleration due to gravity at the center of the earth?
g = 9.81 m/s2 = 32.2 ft/s2the above is a wrong answer. that's g on the surface of the earth.g varies and actually decreases as we move up or down the surface. g at the centre of any spherical body due to it's own mass is 0. So g at the centre of earth is zero.
What is the value of delta g at melting point?
At the melting point, the solid and liquid phases are in equilibrium so the value of delta G is zero.
Who believed in 340BC that the earth was the centre of your solar system?
g
What is the force of gravitation between the earth and a body at the centre of earth?
The gravitational force between the earth and a body at the center of the earth would be 0 Newtons or 0 lbf. F=G (m1*m2)/r^2 r = zero if the center of the body is at the center of the earth
