the answer is so easy if it is converted into v peak to peak. there is confusion in your given question becusase same thing is given to convert, how it is possible.
RMS*SQRT(2)=V(peak)or115V*1.414= 162.63V(peak)Source: What_is_the_conversion_for_rms_voltage_to_peak_to_peak_voltage
Vrms = Vpp/squareroot(2)This can be written another way:Vrms * squareroot(2) = VppAnswerThe question asks for the relationship between the rms value of voltage, and the peak-to-peak value of voltage, not the peak value (Vmax) of voltage, so:Vp-p = 2 Vmax = 2(1.414) Vrms = 2.828 Vrms
To convert from Vrms (voltage root mean square) to Vac (voltage alternating current peak), you can use the formula: Vac = Vrms × √2. For 56.56 Vrms, the calculation would be: 56.56 × √2 ≈ 80.00 Vac. Thus, 56.56 Vrms is approximately 80.00 Vac.
peak value =rms value*1.414 =220*1.414 =311v
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
Vrms=sqrt[1/T * integral(v^2(t)dt, 0,t] Irms=sqrt[1/T * integral(i^2(t)dt, 0,t]
RMS is an average. If you have a 50% duty square wave, the average will be 1/2 the peak. for a 33.3% duty cycle, the average will be 1/3 the peak, etc. VRMS = Vpeak x duty cycle
The RMS value of an AC voltage is VRMS = VPEAK / sqrt(2), where VPEAK = the voltage peak to neutral.AnswerThe average value of a sinusoidal a.c. voltage is zero.
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
Vp=2 Vdc=50 r=Vrms/Vdc Vrms=Vp/1.121 so r=0.028
Actually ,Vrms is the root mean square voltage for example, consider voltages 5V,10V,2V So Vrms is the root value of {[(5*5)+(10*10)+(2*2)]/3} And Vpeak is 10V Thanks!!!!!(Zayed)