I presume you mean wired to four ohms amplifier output:
In this case, pair the two speakers in in series which will make the give you 18 Ohms and then join the two pairs in parallel which will result in approximately eight ohms. Then connect then in that format to the amplifier. It will work for you.
No. Two 16 ohm speakers connected together are either 32 ohms, if wired in series, or 8 ohms, if wired in parallel. You can, however, connect four 16 ohm speakers in series-parallel to get 16 ohms, with four times the power handling capacity of just one.
wire two 8 ohm speakers in a parallel circuit!
Speakers can be wired in parallel or in series. Take the speaker wire from the output, and wire the speakers like so: (ignore the squiggles, they represent spaces) ----|------| S S ----|------| For a parallel wiring. This will reduce the impedance of each speaker, though, so two ohm speakers should be used insead of four ohm speakers. Wire them like this: ----| S | S ----| for series wiring. This will increase impedance though, so eight ohm speakers should be bought instead of four. You will be fine using four ohm speakers in either case, but will lose clarity.
No, you can't get 8 ohms with 4 16-ohm speakers. Here are the possible wirings: +o-+o-+o-+o- all in series: 64 ohms |+o-+o-| |+o-+o-| series parallel: 16 ohms |+o-| |+o-| |+o-| |+o-| all in parallel: 4 ohms .... Well in the conventional way it is not possible. But think of the speakers as load attached to the secondary of some transformer while the primary coil is attached to the amplifier block before (a tuned amplifier type). If we adjust the turns ratio as n = primary:secondary = Sqrt(2):1, then the eefective load on the amplifier would be Reff = n^2*Rp. Now as pointed in the parallel connection, Rp = 4. So, Reff = 8 Ohm.
yes you can you will have to wire up the speakers in parallel because with 8ohm it gives too much resistance and the amp will produce unwanted sound i.e. low volume.
To wire two 8-ohm speakers together while maintaining an 8-ohm total impedance, connect them in parallel. This means you should connect the positive terminals of both speakers together and the negative terminals together, then connect the paired terminals to your amplifier. The formula for calculating impedance in parallel is 1/R_total = 1/R1 + 1/R2; thus, two 8-ohm speakers in parallel result in a total impedance of 4 ohms. To stay at 8 ohms, you can wire one speaker in series with another 8-ohm speaker, resulting in a total impedance of 16 ohms or use a different configuration or additional speakers.
Typical car stereos run speakers at 4 to 8 ohms, so I would wire the two 16 ohm speakers in parallel to get a net 8 ohms. Anything over that would be a little much for a car stereo. You don't need to drive it that hard.
If the diameter of the circular wire is doubled, the resistance will decrease by a factor of four, resulting in a resistance of 0.25 ohms. Resistance is inversely proportional to the cross-sectional area of the wire, which is affected by the diameter.
You can wire and amp down to 0.3 ohms by decreasing its windings.
You can't. Two 4 ohm speakers in parallel equal 2 ohms, and two in series equal 8 ohms. It is possible to wire four 4 ohm speakers so that the load is 4 ohms though. Put two in series (8 ohms). put the other two in series (8 ohms). Then put the two sets in parallel (two 8 ohm sets in parallel equal 4 ohms).
it has to do with ohms and the gauge of the wire. if you have a low ohms then you can't use a small thin wire. because the more ohms the more resistance. if you have a low omhs on a thin wire it can cause the wire to heat up. posibly catch fire.
Yes.