It depends upon the weight of the car, the coefficient of friction for the brake linings, and the type of tire and contact with the road surface. A Formula One car can stop in these conditions very quickly. See this link for further explanation: http://www.csgnetwork.com/stopdistinfo.html A calculator can be found here: http://www.Oregon.gov/OSP/PATROL/stop_brake_distance_chart.shtml Using the calculations from this website's downloadable EXCEL sheet shows that a vehicle traveling 197 mph and weighing 4000 pounds would take 1764 feet to stop with a drivers reaction time of .5 seconds considering the coefficient friction value of .8 which would be considered an ABS brake system with excellent tires.
When traveling 30-mph, the braking distance is 45-feet, and the total stopping distance is 75-feet. This is the length of a semi-truck and trailer.
Stopping Distance = about 315 feet at 70 mph
1/2
Yes it will need the stopping distance of a automobile traveling at the same speed and then it will need a few hundred more feet as well.
Stopping distance at 30mph = 23m
Stopping Distance = 15 feet
At 20 mph, the average thinking distance is around 20 feet, while the braking distance is approximately 20 feet as well. Therefore, the overall stopping distance for a vehicle traveling at 20 mph would be around 40 feet.
4.6 meters or 15ft. is the estimated stoping distance of a vehicle travelling at 25 MPH. Thinking time and weather or not you are sober have not been taken into account.
1/2 mile
The stopping distance of a car traveling at 60 MPH can vary based on factors like road conditions and the vehicle's braking system. On average, the total stopping distance is about 180 feet, which includes the reaction distance (approximately 66 feet) and the braking distance (around 114 feet). This means it takes time for the driver to react and then for the car to come to a complete stop. Always consider safety measures and maintain a safe following distance.
Stopping distance at 40mph = 36m
Stopping Distance = about 146.25 feet.