10 m/s
500
The kinetic energy of the dog can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass of the dog (10 kg) and v is the velocity (5 m/s). Plugging in the values, KE = 0.5 * 10 kg * (5 m/s)^2 = 125 Joules.
Let's see. KE = 1/2mV^2 Bullet: KE = 1/2(0.0020 kg)(400 m/s)^2 = 160 Joules ------------------------------- Ocean Liner: KE = 1/2(6.4 X 10^7 kg)(10 m/s)^2 = 3.2 X 10^9 Joules ----------------------------- The linear by a long shot!
The kinetic energy of the diver can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values for the mass (60 kg) and velocity (10 m/s), we get KE = 0.5 * 60 * 10^2 = 3000 J. Thus, the kinetic energy of the 60-kg diver falling at 10 m/s is 3000 Joules.
The kinetic energy (Ek) of the soccer ball can be calculated using the formula: Ek = 0.5 * mass * velocity^2. Plugging in the values, Ek = 0.5 * 1 kg * (10 m/s)^2 = 50 J. The kinetic energy of the soccer ball is 50 Joules.
In physics, energy is measured in joules (J), which is the amount of work done by a force of one newton acting over a distance of one meter. Therefore, 500 joules represents the amount of energy transferred or converted in a system. To put it into perspective, 500 joules of energy could be equivalent to lifting a 50-kilogram object to a height of 10 meters against the force of gravity.
500 n is a force created by a mass (500 / 9.807) = 50.98 kg so: potential energy = m * g * h = 50.98 * 9.807 * 10 = 5000 joules. . if it was 500 kg (not newtons) weight, then m*g*h = 500 * 9.807 * 10 = 49035 joules.
The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object. Plugging in the values, we get PE = 10 kg * 9.8 m/s^2 * 1 m = 98 Joules.
The 10 KG is a distraction. 500m in 25 seconds = 500/25=20 m per second.
2000 joules
The object's kinetic energy is 78.4 joules.
Potential energy = m G H = (100 kg) (9.8 m/s2) (10 m) = 9,800 kg-m2/s2 = 9,800 joules9,800 joules is the correct answer to this question
energy required to lift up 10kg=10x9.81x4=392.4 joule. enegy produced by the engine=500 joule efficiency=392.4/500=78.48%
The potential energy gained by the object is 1,000 Joules. Potential energy is calculated using the formula PE = mgh, where m is the mass of the object (10 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height the object is lifted (10 meters).
The potential energy of an object is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. Plugging in the values of m = 100 kg, g = 9.81 m/s^2, and h = 10 m, we get PE = 1009.8110 = 9810 J. So, the potential energy of the 100 kg mass 10 meters above the ground is 9810 Joules.
The potential energy gained by lifting a 10 kg object up 10 meters can be calculated using the formula: Potential Energy = mass x gravity x height. In this case, the potential energy gained would be 10 kg x 9.8 m/s^2 x 10 m = 980 Joules. This means that the object has gained 980 Joules of potential energy as a result of being lifted 10 meters above the ground.
KE = 1/2mass velocity squared KE = 1/2mV^2 80 J = 1/2(10 kg)V^2 multiply through by 2 160 = 10V^2 divide by 10, both sides 16 = V^2 take square root each side and discard negative answer Velocity = 4 m/s