10 m/s
500
The kinetic energy of the dog can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass of the dog (10 kg) and v is the velocity (5 m/s). Plugging in the values, KE = 0.5 * 10 kg * (5 m/s)^2 = 125 Joules.
Let's see. KE = 1/2mV^2 Bullet: KE = 1/2(0.0020 kg)(400 m/s)^2 = 160 Joules ------------------------------- Ocean Liner: KE = 1/2(6.4 X 10^7 kg)(10 m/s)^2 = 3.2 X 10^9 Joules ----------------------------- The linear by a long shot!
The kinetic energy of the diver can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values for the mass (60 kg) and velocity (10 m/s), we get KE = 0.5 * 60 * 10^2 = 3000 J. Thus, the kinetic energy of the 60-kg diver falling at 10 m/s is 3000 Joules.
The kinetic energy (Ek) of the soccer ball can be calculated using the formula: Ek = 0.5 * mass * velocity^2. Plugging in the values, Ek = 0.5 * 1 kg * (10 m/s)^2 = 50 J. The kinetic energy of the soccer ball is 50 Joules.
500 joules is equal to 368.78 ft-lbf. For example, an object has 500 joules of kinetic energy, when its mass is 10 kg (~22 lbs) and it is traveling at 10 m/s (36 km/h or ~38.2 ft/s). Second example: The muzzle energy of a traveling 9mm bullet is around 500 joules. Third example: An object with mass of 5kg (11 lbs) and which is raised at 10 metres (32.8 ft) has around 500 joules of potential energy. So, 500 joules is quite much. Getting hit with an object which has 500 joules of kinetic energy can be lethal.
500 n is a force created by a mass (500 / 9.807) = 50.98 kg so: potential energy = m * g * h = 50.98 * 9.807 * 10 = 5000 joules. . if it was 500 kg (not newtons) weight, then m*g*h = 500 * 9.807 * 10 = 49035 joules.
The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object. Plugging in the values, we get PE = 10 kg * 9.8 m/s^2 * 1 m = 98 Joules.
The 10 KG is a distraction. 500m in 25 seconds = 500/25=20 m per second.
2000 joules
The object's kinetic energy is 78.4 joules.
Potential energy = m G H = (100 kg) (9.8 m/s2) (10 m) = 9,800 kg-m2/s2 = 9,800 joules9,800 joules is the correct answer to this question
energy required to lift up 10kg=10x9.81x4=392.4 joule. enegy produced by the engine=500 joule efficiency=392.4/500=78.48%
The potential energy of an object is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. Plugging in the values of m = 100 kg, g = 9.81 m/s^2, and h = 10 m, we get PE = 1009.8110 = 9810 J. So, the potential energy of the 100 kg mass 10 meters above the ground is 9810 Joules.
The potential energy gained by the object is 1,000 Joules. Potential energy is calculated using the formula PE = mgh, where m is the mass of the object (10 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height the object is lifted (10 meters).
The potential energy gained by lifting a 10 kg object up 10 meters can be calculated using the formula: Potential Energy = mass x gravity x height. In this case, the potential energy gained would be 10 kg x 9.8 m/s^2 x 10 m = 980 Joules. This means that the object has gained 980 Joules of potential energy as a result of being lifted 10 meters above the ground.
KE = 1/2mass velocity squared KE = 1/2mV^2 80 J = 1/2(10 kg)V^2 multiply through by 2 160 = 10V^2 divide by 10, both sides 16 = V^2 take square root each side and discard negative answer Velocity = 4 m/s