They will produce gametes that are also homozygous.
The dominant parent is most likely homozygous dominant, and the recessive parent has only the homozygous genotype. So the dominant parent can pass on only dominant alleles for this trait, and the recessive parent can pass on only recessive alleles for this trait. So all of the offspring would be heterozygous and have the dominant phenotype.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
Because Mendel crossed two pure-breeding plants. One being homozygous dominant and one being homozygous recessive. All of the progeny ended up being heterozygous, causing them to take on the dominant phenotype and look like the homozygous dominant parent.
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.
The dominant parent is most likely homozygous dominant, and the recessive parent has only the homozygous genotype. So the dominant parent can pass on only dominant alleles for this trait, and the recessive parent can pass on only recessive alleles for this trait. So all of the offspring would be heterozygous and have the dominant phenotype.
Let the dominant allele, red color, be represented by R,and the recessive alelle, yellow, by r. Both parent plants are homozygous, so their genotypes will be: Red: RR Yellow: rr The cross is therefore: RR X rr Remember that a homozygous genotype can produce only one type of gamete, so the red plant can only produce gametes with R, and the yellow plant can only produce r gametes. Since the F1 generation takes one gamete frrom each parent, and each parent can only produce one type of gamete, then the F1 generation can have only one genotype: F1: Rr That is, all of the offspring from this cross will be heterozygous. Red is dominant over yellow, and all of the offspring carry one R allele, therefore all of the F1 generation will be red in color.
100 percent
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
If one parent is homozygous dominant for all traits (carrying two dominant alleles for each trait), and the other parent is heterozygous (carrying one dominant and one recessive allele for each trait), there would be a 100% chance that the baby would inherit the dominant alleles from the homozygous dominant parent. Therefore, the baby would also be heterozygous for all the traits, carrying one dominant and one recessive allele for each trait.
If the parent generation consisted of a homozygous dominant parent and a homozygous recessive parent, then the F1 generation would be 100% heterozygous.
Male
Male
A heterozygous cross.Tt X TtOne homozygous dominant--TTTwo heterozygous dominant---TtOne homozygous recessive--ttAll on a statistical average outcome.
Rr
"Heterozygous" and "homozygous" are terms that refer to alleles, which, in genetics determine what trait, from which parent, will appear in the offspring. Alleles can be either Dominant or Recessive. Every organism has two alleles, which can both be dominant, both recessive, or one of each.So,If an organism heterozygous, it has one recessive and one dominant allele.If an organism is homozygous then both of its alleles are the same; you need to specify if they are homozygous recessive (both alleles are recessive) or homozygous dominant (both alleles are dominant).
The only possible outcome is EeWw, which will express the dominant genes but carry the recessive ones. They get one chromosome from each parent, but since the parents all have matching chromsomes in this case then it doesn't matter which one they get. Since one parent has EE, E is the only one that can be passed on. Since the other has ee, they can only pass on e. Therefore, the child can only possible have Ee, as they get one from each parent.