They will produce gametes that are also homozygous.
The dominant parent is most likely homozygous dominant, and the recessive parent has only the homozygous genotype. So the dominant parent can pass on only dominant alleles for this trait, and the recessive parent can pass on only recessive alleles for this trait. So all of the offspring would be heterozygous and have the dominant phenotype.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
The offspring will get the traits of Homozygous BB .
The dominant parent is most likely homozygous dominant, and the recessive parent has only the homozygous genotype. So the dominant parent can pass on only dominant alleles for this trait, and the recessive parent can pass on only recessive alleles for this trait. So all of the offspring would be heterozygous and have the dominant phenotype.
Let the dominant allele, red color, be represented by R,and the recessive alelle, yellow, by r. Both parent plants are homozygous, so their genotypes will be: Red: RR Yellow: rr The cross is therefore: RR X rr Remember that a homozygous genotype can produce only one type of gamete, so the red plant can only produce gametes with R, and the yellow plant can only produce r gametes. Since the F1 generation takes one gamete frrom each parent, and each parent can only produce one type of gamete, then the F1 generation can have only one genotype: F1: Rr That is, all of the offspring from this cross will be heterozygous. Red is dominant over yellow, and all of the offspring carry one R allele, therefore all of the F1 generation will be red in color.
100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
When you say homozygous, you're talking about genes. It's almost impossible, or not known, if a human has had genes of all homozygousity.
If one parent is homozygous dominant for all traits (carrying two dominant alleles for each trait), and the other parent is heterozygous (carrying one dominant and one recessive allele for each trait), there would be a 100% chance that the baby would inherit the dominant alleles from the homozygous dominant parent. Therefore, the baby would also be heterozygous for all the traits, carrying one dominant and one recessive allele for each trait.
If the parent generation consisted of a homozygous dominant parent and a homozygous recessive parent, then the F1 generation would be 100% heterozygous.
Two types: A heterozygous parent (Aa) and a homoygous recessive parent (aa) can produce phenotypically dominate and phenotpically recessive offspring (with 50% genotypes Aa and the other 50% aa). If the genes are co-dominate then the offspring can have blended traits and recessive traits phenotypically.
Male
Rr
A heterozygous cross.Tt X TtOne homozygous dominant--TTTwo heterozygous dominant---TtOne homozygous recessive--ttAll on a statistical average outcome.