His daughter.
BBkk as there is no other alleles present for the man to inherit. the father can only pass on a B allele and a k allele and the mother can also only pass on a B allele and a k allele.
He will pass this harmful sex-linked gene on to his daughters. Sons will inherit their Y chromosome from their father, not his X chromosome.
As long as you aren't talking about a trait or gene that behaves co-dominately or some other exception, the man would have the dominant trait show up and his alleles would be dominant and recessive (or Dd if you are using letter symbols for the alleles- upper case being the dominant allele from the mom's egg and lower case for the recessive allele from the dad's sperm). So for example if we are talking about the gene for earlobes we can use the letter E to represent the two alleles or genetic variations: E for un-attached earlobes and e for attached earlobes. A sex cell (sperm or egg) has one allele each so that when they unite to make an embryo the new person has 2 alleles- one from each parent. So if the man inherited a dominant allele E from his mom and a recessive allele e from his father then he would have Ee as his "genotype"(what alleles he has). His "phenotype" is what trait he shows, which would be what ever is dominant-- in this case E equals un-attached earlobes.
Yes, a man with blood type B and a woman with blood type AB can have a child with blood type B. The child would inherit one allele for blood type B from the father and either an A or B allele from the mother. The child's blood type could be either B or AB.
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]
BBkk as there is no other alleles present for the man to inherit. the father can only pass on a B allele and a k allele and the mother can also only pass on a B allele and a k allele.
If a man is heterozygous for the alleles that cause the condition and has children with a woman who lacks that defective allele, there is a 50% chance that each of their children will inherit the defective allele. This is because the man can pass on either the normal or defective allele, resulting in a 50% chance of passing on the defective allele.
A man with a genotype of Cc means he has one allele for the dominant trait (C) and one allele for the recessive trait (c). This genotype indicates that he carries both versions of the gene and can pass on either the dominant or recessive trait to his offspring. The expression of the dominant or recessive trait will depend on how the alleles interact with each other.
Yes, if the mother's genotype is BO, she may pass the O allele on to the child and it will be type O.
He would have the recessive phenotype for that trait.
He will pass this harmful sex-linked gene on to his daughters. Sons will inherit their Y chromosome from their father, not his X chromosome.
It depends on the two alleles the man carries; if he is carrying HH- it is a 100% chance, because HD is autosomal dominant. If his allele is Hh, it is a 50% chance.
All of their children will have straight hair, as the father can only pass on the dominant straight hair allele. The children will inherit one straight hair allele from their father and one curly hair allele from their mother, but the dominant straight hair allele will mask the recessive curly hair allele.
She inherited brown eyes, a dominant allele in both her parents.
True
There is a 75% chance that their children will have freckles and a 25% chance that their children will not have freckles. This is because both parents are carriers of the freckles allele and can pass it on to their offspring.
a porter or bell man