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Why is a son who receives the allele for color blindness from his mother always colorblind?
Color blindness is a sex-linked trait that is carried on the X chromosome. Since males inherit their single X chromosome from their mother, if the mother carries the allele for color blindness, her son will inherit it and be colorblind. Females need two copies of the allele to be colorblind, so they can be carriers without exhibiting the trait.
What must occur for a girl to be color blind?
The girl must have a copy of the gene on each X chromosome. This means that she must have a father who is colorblind and a mother who is either a carrier or is colorblind.
Why is it not possible to get a colorblind female from a normal male and a heterozygous female?
Color blindness is typically inherited as an X-linked recessive trait. A colorblind female must have two copies of the colorblind allele (one from each parent), meaning she must inherit the allele from both her mother and father. In this scenario, the normal male (with a normal X chromosome) can only pass on a normal X chromosome to his daughters, while the heterozygous female has one normal X and one colorblind X, meaning she can pass on either allele. Therefore, the combination of a normal male and a heterozygous female cannot produce a colorblind daughter.
A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
What is the probability a woman heterozygous for an x-linked trait will have a son with a genetic disorder if the genetic disorder is recessive?
The probability would be 0.5 or 50%. A heterozygous woman will pass on the X chromosome with the recessive allele to 50% of her sons, and since the disorder is recessive, the son would only have the disorder if the X chromosome with the recessive allele is inherited from the mother.
What is the genotype if a brown eyed persons mother was color blind and his father had blue eyes who's engaged to a person who's color blind whos father is normal vision?
The brown-eyed person likely has the genotype Bb for eye color, where B represents the brown allele and b represents the blue allele. Since the mother is colorblind (XbXb), she contributes an X chromosome with the colorblind allele. The father with blue eyes (bb) does not affect the X-linked colorblind trait. The engaged partner, being colorblind with a normal-vision father (XbY), would also have the genotype XbXb.
Colorblind male not colorblind female can there kid be color blind?
He will always be colorblind in that case because the defective gene is carried on the "X" chromosome, which males only have one of. You see, the colorblindness gene is recessive, which means if it is paired with a regular color seeing gene it is hidden, and the person can still see the difference between red and green. Because males have only one "X" chromosome, if they get the colorblindness gene from their mother, it will always lead to colorblindness. Side note: Males cannot receive the colorblindness gene from their Father, as he cannot give a "X" chromosome to his son. If he did, his son would be a daughter.
What if Mary and her mother are both colorblind is Mary's father colorblind too?
If Mary's mother is colorblind, and therefore carries the colorblind gene on one of her X chromosomes, then Mary would inherit that gene as well. If Mary's father is colorblind, he would have to pass on his X chromosome with the colorblind gene to Mary, making her colorblind too. If only Mary's mother is colorblind, Mary's father is likely not colorblind.
If a mom colorblind and the father not colorblind what is the probability the child will be colorblind?
If the mother is a carrier of the colorblind gene (XcX) and the father has normal color vision, the probability of their child being colorblind is 50%. This is because the child has a 50% chance of inheriting the Xc chromosome from the mother and developing colorblindness.
Father isn't colorblind mother is a carrier--one son is colorblind but the other is not how?
It is called x-linked alleles. It is rare for a female to have color blindness because the allele must be passed from both parents. Males only need one allele to be color blind.With the equation, color blind female and non-color blind male reproduce. Each son has a 50% chance of developing the disorder.
Why do all the daughters in generation 2 carry the colorblind gene?
In genetics, if a colorblind gene is located on the X chromosome, all daughters in generation 2 would inherit this gene from their father, who carries the colorblind trait. Since daughters receive one X chromosome from each parent, they will inherit their father's X chromosome carrying the colorblind gene, while receiving a second X chromosome from their mother. This results in all daughters being carriers of the colorblind gene. If the mother is not a carrier, the daughters will not express colorblindness but will carry the gene.
Why are men more likely than women to be colorblind?
Yes. Because the colorblind trait is a sexlinked trait and is found in the X chromosome that is inherited from the mother, men that only have one X chromosome will develop colorblindness if the trait is found in this gene. For a woman to get it, she would need to have the colorblind gene on both x chromosomes. Therefore the girl´s dad would have to be colorblind and the mother at least a carrier.
