The brown-eyed person likely has the genotype Bb for eye color, where B represents the brown allele and b represents the blue allele. Since the mother is colorblind (XbXb), she contributes an X chromosome with the colorblind allele. The father with blue eyes (bb) does not affect the X-linked colorblind trait. The engaged partner, being colorblind with a normal-vision father (XbY), would also have the genotype XbXb.
The genotype of the father is certainly OO (because blood type O is recessive). The genotype of the mother however can be AO or AA (both give blood type A). The baby will have a combination of the genes from the mother and the father (one of each) and so: - If the genotype of the mother is AA and the genotype of the father is OO, the baby will certainly have AO as genotype and has therefore blood type A. -If the genotype of the mother is AO and the genotype of the father is OO, the baby can have AO or OO as genotype. AO results in blood type A and OO in blood type O (50% chance).
If the mother's genotype is AA, the child can be A+ or A- If the mother's genotype is AO, the child can be A+, A-, O+, or O- Most likely A+
The genotype of the father is certainly OO (because blood type O is recessive). The genotype of the mother however can be AO or AA (both give blood type A). The baby will have a combination of the genes from the mother and the father (one of each) and so: - If the genotype of the mother is AA and the genotype of the father is OO, the baby will certainly have AO as genotype and has therefore blood type A. -If the genotype of the mother is AO and the genotype of the father is OO, the baby can have AO or OO as genotype. AO results in blood type A and OO in blood type O (50% chance).
The mother will produce two types of gametes: IA and IO (mother is A) The father is AB his genotype is IAIB, thus he will produce these kind of gametes: IA and IB Four combinations are possible IA from Mother and IA from Father: The child has genotype IAIA and he has blood group A IO from Mother and IA from Father: The child has genotype IAIO and he has blood group A IA from Mother and IB from Father: The child has genotype IAIB and he has blood group AB IO from Mother and IB from Father: The child has genotype IBIO and he has blood group B Thus the phnotypic ratio is blood group A:B:AB = 2:1:1
50% AA and 50% Aa
The mother would have to be type A. Father has genotype (0,0) Mother would need to have genotype (A,0) - fenotype (blood group) = A
The mother is genotype AB, the father is either genotype BO or BB. If the father is genotype BO, the children can be genotype AB, AO, BB, or BO. This results in children with phenotype blood types of: AB, A, or B. If the father is genotype BB, the children can be genotype AB, AB, BB, or BB. This results in children with phenotype blood types of: AB or B.
The mother is genotype AB, the father is either genotype BO or BB. If the father is genotype BO, the children can be genotype AB, AO, BB, or BO. This results in children with phenotype blood types of: AB, A, or B. If the father is genotype BB, the children can be genotype AB, AB, BB, or BB. This results in children with phenotype blood types of: AB or B.
It is not possible. NO
The mother is genotype AB, the father is either genotype BO or BB. If the father is genotype BO, the children can be genotype AB, AO, BB, or BO. This results in children with phenotype blood types of: AB, A, or B. If the father is genotype BB, the children can be genotype AB, AB, BB, or BB. This results in children with phenotype blood types of: AB or B.
depends... were they homozygous or heterozygous?
Because the actuality of IAIA is actually A then the father would be type A and the mother being type O they would produce children of Type A blood type. For the answer I chose A) A... I just had this on my Bio exam.