The rate of diffusion would be faster for the right cylinder.
A sphere has the lowest surface area to volume ratio of all geometric shapes. This is because the sphere is able to enclose the largest volume with the smallest surface area due to its symmetrical shape.
0.6 apex(: and yall only got this cuz of mee(: KB
108m3
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
Your tank is a cylinder with hemispherical end caps. Although you said "cylindrical midsection," we will interpret that to mean the height, h, of the cylinder, which is six feet. We also infer that the radius of the sphere is equal to the radius of the cylinder, which must be the case if the tank has hemispherical end caps. So, the volume of the tank is equal to the sum of the volumes of the two hemispheres and the cylinder.The equation for the volume of a cylinder is V = pi*r2*h. If you put the two hemispheres together, you have a sphere whose volume is V = (4/3)*pi*r3.So, V = (4/3)*pi*r3 + pi*r2*h = pi*r2*(4r/3 + h),where h = 6 in this case.
volume of a regular right circular cylinder is V=pi(r2)h since the radius is (a) then the height of the circular cylinder would be (2a) so the volume of the largest possible right circular cylinder is... V=2(pi)(r2)(a) with (pi) being 3.14159 with (r) being the radius of the circle on the top and bottom of the cylinder with (a) being the radius of the sphere
it would be faster for the right cylinder
He discovered the relationship between a sphere and a circumscribed cylinder of the same height and diameter. The volume is 4⁄3πr3 for the sphere, and 2πr3 for the cylinder. The surface area is 4πr2 for the sphere, and 6πr2 for the cylinder (including its two bases), where r is the radius of the sphere and cylinder. The sphere has a volume and surface area two-thirds that of the cylinder. A sculpted sphere and cylinder were placed on the tomb of Archimedes at his request.
If a sphere with a surface area to volume ratio of 0.3 m⁻¹ and a right circular cylinder with a ratio of 2.1 m⁻¹ were compared, we would expect the cylinder to have a significantly larger surface area relative to its volume compared to the sphere. This suggests that the cylinder would have a greater ability to exchange heat or matter with its environment, making it more efficient for processes like cooling or absorption. The sphere, being more compact, would likely retain heat or matter more effectively. Overall, the two shapes would demonstrate contrasting behaviors in applications involving surface interactions.
The rate of diffusion would be faster for the right cylinder.
the cylinder is approximately 50240 m3 the sphere is approximately 33493 and 1/3 m3
C- The rate of diffusion would be faster for the right cylinder
Some of many examples are:- Finding the circumference of a circle Finding the area of a circle Finding the surface area of a sphere Finding the volume of a sphere Finding the surface area of a cylinder Finding the volume of a cylinder Finding the volume of a cone Finding the surface area of a cone
It depends on what r is and on what information you have. Even if r is a radius of a circular shape, you would have different formulae depending on whether: it is a sphere and you have the volume, it is a sphere and you have the surface area, it is a circle and you have the area, it is a circle and you have the circumference, it is a circle and you have the length and angle of an arc, it is a cone and you have volume and height, it is a cylinder and you have volume and height etc.
A cylinder filled with water has properties such as volume, surface area, and weight. The volume of water in the cylinder is determined by its height and radius. The surface area of the cylinder is the total area of its curved surface and two circular bases. The weight of the water in the cylinder is influenced by its volume and density.
A spectacular landmark in the history of mathematics was the discovery by Archimedes (287-212 B.C.) that the volume of a solid sphere is two- thirds the volume of the smallest cylinder that surrounds it, and that the surface area of the sphere is also two-thirds the total surface area of the same cylinder.
The ratio of surface area to volume for a sphere is given by the formula ( \frac{3}{r} ), where ( r ) is the radius. For the sphere with a ratio of 0.3 m(^{-1}), we can deduce that its radius is 10 m. For the right circular cylinder, the ratio of surface area to volume is given by ( \frac{2}{h} + \frac{2r}{h} ), where ( r ) is the radius and ( h ) is the height; a ratio of 2.1 indicates specific dimensions that would need to be calculated based on chosen values for ( r ) and ( h ).