A test cross made for a heterozygous recessive trait would show a dominant gene and a recessive gene. The cat would have one dominant gene (A) and 1 recessive (a).
The homozygous recessive individual is used in a test cross to determine the genotype of an individual with a dominant phenotype but unknown genotype. When crossed with a homozygous recessive individual, if any offspring display the recessive trait, it indicates that the unknown individual is heterozygous for that trait.
When writing a genotype in a scientific report or research paper, it is important to use the correct format. This typically involves using the specific letters that represent the alleles for a particular gene. For example, if discussing a gene with two alleles, one dominant and one recessive, you would write the genotype as two letters, with the dominant allele capitalized and the recessive allele lowercase. It is also important to provide context and explain the significance of the genotype within the study.
Both parents would each have one dominant gene for normal pigmintation and each would have one recessive albino gene. Say P is the dominant gene and q is the albino gene. Then the parents genotype would both be Pq. Below is a Punnet Square. The child's genotype is qq P q ------------------------------------- P / PP / Pq (carrier) / / / / ///////////////////////////////////////// q / Pq (carrier) / qq (albino) / / / / ////////////////////////////////////////
Yes, our genotype refers to the specific genetic makeup we inherit from our parents, which remains constant throughout our lives. Therefore, we always have the same genotype, which is unique to each individual. However, this genetic information may not always be readily apparent without specific testing.
identical twins could not be produced because there is only suppose to be 2 gametes which is one dominant and one recessive though there can´t be only one gamete i dont know if this answer makes sense but i dont know either if its right
The homozygous recessive individual is used in a test cross to determine the genotype of an individual with a dominant phenotype but unknown genotype. When crossed with a homozygous recessive individual, if any offspring display the recessive trait, it indicates that the unknown individual is heterozygous for that trait.
No, I think you have your terms confused.The terms "dominant" and "recessive" are applied to alleles of a genotype. A genotype is an expression (using upper- and lower-case letters) that shows what alleles an organism has for a particular locus. The two alleles (in most cases) inherited (one from mother and one from father) can either be dominant or recessive. The recessive allele is not fully expressed in the presence of the dominant allele and is only expressed when there are two recessive alleles. The genotype could be called "recessive" I suppose if the genotype is homozygous recessive. But remember that two recessive alleles as a genotype is only one possibility - in which case you can't say the "genotype is recessive".The phenotype is dependent on the genotype. If present, the dominant alleles (in simple Mendelian genetics) will determine the phenotype - what the organism's trait or characteristic is. The phenotype will never be what is coded by the recessive allele unless the genotype is two recessive alleles.
This is one of the classic experiments carried out by Gregor Mendel. If you cross pure-breeding green pod plants with pure-breeding yellow pod plants the offspring (F1 generation) will all have green pods. This means that green pod is dominant and yellow pod is recessive. To explain the results, pure-breeding green pod plants must have the genotype GG (homozygous dominant) and yellow pod plants must be gg (homozygous recessive). When they are crossed the F1 offspring will receive a G allele from the green parent and a g allele from the yellow parent, so they will all have the genotype Gg ie they will be heterozygous.
Mendel's principle of dominant and recessive alleles doe not explain why the heterozygous chickens have both red and white hair
When writing a genotype in a scientific report or research paper, it is important to use the correct format. This typically involves using the specific letters that represent the alleles for a particular gene. For example, if discussing a gene with two alleles, one dominant and one recessive, you would write the genotype as two letters, with the dominant allele capitalized and the recessive allele lowercase. It is also important to provide context and explain the significance of the genotype within the study.
A male with red-green color blindness has the genotype X^cY, where X^c represents the X chromosome carrying the recessive allele for color blindness. He inherited the recessive allele from his mother, who must have at least one X chromosome with the color blindness allele (either X^cX or X^cY). Since males inherit their X chromosome from their mothers and their Y chromosome from their fathers, the mother's genotype determines whether the son will express the condition.
Yes to the first one, no to the second one. Firstly, widow's peak is caused by a dominant gene while a straight hairline is caused by a recessive gene. Let 'H' be dominant and 'h' be recessive. So for a dominant gene, the trait still will be expressed whether the genotype of the person is homozygous dominant(HH) or heterozygous(Hh). For a recessive gene however, the trait will only be expressed when the genotype of the person is homozygous recessive (hh). So two people with a widow's peak CAN have a child with a stright hairline, provided both of their genotypes are Hh. This is because by crossing their genotypes, they can have a possibility of having child with the genotype HH(widow's peak), Hh(widow's peak), and also hh(straight hairline). The ratio of these three possibilities however, are 1:2:1. So the odds of having a child with a straight hairline in this case is 1:3. If the two people who have widow's peak have the genotype HH or one of them HH and the other Hh, then the possibility of having a child with a straight hairline is 0. This is because by crossing their genotypes together, the genotype of the child will either be HH for the first case, and HH or Hh for the second case. For two people who have a straight hairline, the genotype of both will definitely be homozygous recessive (hh), thus child will definitely have the recessive gene. Therefore, it is not possible for two people with straight hairline to have a child with widow's peak.
it would be t recie
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Both parents would each have one dominant gene for normal pigmintation and each would have one recessive albino gene. Say P is the dominant gene and q is the albino gene. Then the parents genotype would both be Pq. Below is a Punnet Square. The child's genotype is qq P q ------------------------------------- P / PP / Pq (carrier) / / / / ///////////////////////////////////////// q / Pq (carrier) / qq (albino) / / / / ////////////////////////////////////////
explain how dominant genes work
BBEe and bbEe. Black is dominant, and brown is recessive. Yellow is also recessive. Because one parent is brown, for none of the puppies to also be brown the black parent cannot carry the recessive allele on the B locus. Because neither parent is yellow but some of the puppies are, both parents must carry the recessive allele on the E locus.