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The Hayze Brand

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3y ago
Updated: 6/22/2024

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What alleles would the offspring have if both parents are pure a or pure A?

If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.


Suppose a women with normal colored skin and having an albino mother married an albino man What would be the genotype of the woman?

The albino woman has to be AA. So the man has to be either AA or Aa in order to be normal. So if they have a baby and its albino it has to contain the AA gene. a a A Aa | Aa ---------------- A Aa | Aa doesn't work.. All outcomes are normal. a a A Aa | Aa ----------------- a AA | AA these combination outcomes 50% chance of an albino baby. This means the man is Aa Heterozygous dominant.. the mother is AA homozygous recessive.. and the baby is the same as the mother. AA...


How can you get a true breeding plant?

You can obtain a true-breeding plant by repeatedly self-pollinating a plant that consistently produces offspring with the same characteristics as the parent. This ensures that the desired traits are consistently passed on without variation.


Can two white people have an albino baby?

Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.


Is AA a homozygous genotype?

homozygous = AA & AA Heterozygous = Aa

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WHAT WAS THE RELATIONSHIP BETWEEN THE BRITISH AND THE AMERICAN INDIANS LIVING IN NORTH AMERICA?

aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa


Does peewee have a girlfriend?

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What song contains the lyrics AA AA AA AA?

Knights of Cydonia by Muse


If all offspring of a cross have the genotype Aa the parents of the crosses would most likely be?

If ALL offspring are Aa, The parents are AA and aa.


What are the notes on the recorder to for one and all?

Recorder: For One And AllAA BB AA GG AA BB A B A AA BB AA GG AA BB A B A BB BB AA G G BB B A A G A BB BB AA G G BB B A A G A AA BB AA GG AA BB A B A AA BB AA GG AA BB A B A


What alleles would the offspring have if both parents are pure a or pure A?

If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.


From the cross AA X AA the probability of producing a homozygous dominat offspring is?

Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).


What is the result if you cross a hetyerozygote to a recessive?

As per a Punnet Square: Aa crossed with aa can result in Aa, Aa, aa, or aa. So 50% heterozygotes, 50% recessives.


Which cross would produce the least phenotypic variation?

There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.


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it is the name of one of the players you have to shoot with the laser it doesn't matter what name of the player just one name of on player a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a aa a a a a a a aa a a a a a aa a a a a a a a a a a a a a a a a a a a a a aa a a aa a aa a a a a a a a a a a a a a a a a a a a a a a a


Suppose a women with normal colored skin and having an albino mother married an albino man What would be the genotype of the woman?

The albino woman has to be AA. So the man has to be either AA or Aa in order to be normal. So if they have a baby and its albino it has to contain the AA gene. a a A Aa | Aa ---------------- A Aa | Aa doesn't work.. All outcomes are normal. a a A Aa | Aa ----------------- a AA | AA these combination outcomes 50% chance of an albino baby. This means the man is Aa Heterozygous dominant.. the mother is AA homozygous recessive.. and the baby is the same as the mother. AA...