aa
If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.
The albino woman has to be AA. So the man has to be either AA or Aa in order to be normal. So if they have a baby and its albino it has to contain the AA gene. a a A Aa | Aa ---------------- A Aa | Aa doesn't work.. All outcomes are normal. a a A Aa | Aa ----------------- a AA | AA these combination outcomes 50% chance of an albino baby. This means the man is Aa Heterozygous dominant.. the mother is AA homozygous recessive.. and the baby is the same as the mother. AA...
You can obtain a true-breeding plant by repeatedly self-pollinating a plant that consistently produces offspring with the same characteristics as the parent. This ensures that the desired traits are consistently passed on without variation.
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.
homozygous = AA & AA Heterozygous = Aa
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yo mama!!:0 that's who he/she is going out with a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a AA a a a a a a a a a AA a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a a
Knights of Cydonia by Muse
If ALL offspring are Aa, The parents are AA and aa.
Recorder: For One And AllAA BB AA GG AA BB A B A AA BB AA GG AA BB A B A BB BB AA G G BB B A A G A BB BB AA G G BB B A A G A AA BB AA GG AA BB A B A AA BB AA GG AA BB A B A
If the parents are both AA, which results in the cross AA X AA, then the offspring will all be AA. If both parents are AA, resulting in the cross AA X AA, then all offspring will be AA. If BOTH parents are Aa, resulting in the cross Aa X Aa, then the offspring will be 25% AA, 50% Aa, and 25% AA. This is only true if the alleles are not sex-linked.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
As per a Punnet Square: Aa crossed with aa can result in Aa, Aa, aa, or aa. So 50% heterozygotes, 50% recessives.
There are two choices that produce the least phenotypic variation. AA times aa produces only Aa offspring. AA times Aa produces and AA and Aa offspring.
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The albino woman has to be AA. So the man has to be either AA or Aa in order to be normal. So if they have a baby and its albino it has to contain the AA gene. a a A Aa | Aa ---------------- A Aa | Aa doesn't work.. All outcomes are normal. a a A Aa | Aa ----------------- a AA | AA these combination outcomes 50% chance of an albino baby. This means the man is Aa Heterozygous dominant.. the mother is AA homozygous recessive.. and the baby is the same as the mother. AA...