As per a Punnet Square:
Aa crossed with aa can result in Aa, Aa, aa, or aa.
So 50% heterozygotes, 50% recessives.
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
If you cross a purebred dominant and a purebred recessive individual, the offspring would be considered hybrids, not purebreds. Purebreds result from breeding within the same purebred line, whereas hybrids are the result of crossing individuals from two different purebred lines.
When two recessive alleles are joined together in an individual, the individual will display the recessive trait associated with those alleles. This is because recessive alleles only express themselves when a dominant allele is not present.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
In a cross between two individuals with a dominant phenotype but carrying a recessive trait, the recessive trait would not be visibly expressed in the offspring (since they don't inherit two copies of the recessive allele). However, they would be carriers of the recessive trait, meaning they could pass it on to future generations.
A cross between a homozygous recessive and an individual of unknown genotype is called a test cross.The homozygous recessive can only pass on a recessive allele to the offspring, and so any recessive in the other parent will show up in the phenotype (detectable characteristics) of some of the offspring.
A test cross between a homozygous recessive and a heterozygous individual will yield 50% of offspring as homozygous recessive. This is because all the offspring will inherit one recessive allele from the homozygous recessive parent.
To determine the genotype of an individual that shows the dominant phenotype you would cross that individual with one that is homozygous recessive. A monohybrid cross of two individuals that are heterozygous for a trait exhibiting complete dominance would probably result in a phenotype ratio is 3 dominant 1 recessive.
A cross between two heterozygous parents (eg. Gg X Gg) would result in a phenotypic ratio of 3 dominant : 1 recessive, and a genotypic ratio of 1GG:2Gg:1gg.GgGGGGggGggg
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
If you cross a purebred dominant and a purebred recessive individual, the offspring would be considered hybrids, not purebreds. Purebreds result from breeding within the same purebred line, whereas hybrids are the result of crossing individuals from two different purebred lines.
When two recessive alleles are joined together in an individual, the individual will display the recessive trait associated with those alleles. This is because recessive alleles only express themselves when a dominant allele is not present.
It depends. If it's a heterozygous cross, (Tt x Tt), there's a 25% chance. If it's a homozygous dominant cross (TT x TT), the chance is 0%. Neither parent has the alleles for a recessive trait, so none of their offspring can have the recessive trait. If it's a homozygous recessive cross (tt x tt), there's a 100% chance. The only alleles the parents can pass on are recessive.
Recessive allele exhibits its trait only when paired with another recessive allele in a genetic cross.
If the cat is suspected to be heterozygous for a recessive trait, the presumed genotype would be Aa, where A represents the dominant allele and a represents the recessive allele. This means the cat has one dominant allele and one recessive allele for the trait in question. The test cross would involve crossing this cat with a homozygous recessive individual to determine the genotype of the cat.
If the traits are both recessive and independently assorting, then 1/16 of the offspring will be recessive for both traits in a dihybrid cross (1/4 for each individual trait, multiplied together).
This is 100% for heterozygous when referring to genes.