the genotype would be for the mom Ee and for the dad it would be Ee.
If both you and your sibling have attached earlobes (aa genotype) and your parents have unattached earlobes, then your parents must both be carriers of the recessive allele for attached earlobes (Aa genotype).
The phenotypes of attached and unattached earlobes do not fit neatly into the Mendelian theory of two alleles for one trait, and there is a continuum of earlobe phenotypes. That said, unattached earlobes are a dominant trait, so if the individual is homozygous for unattached earlobes, all of her offspring will have the unattached phenotype, even if some or all of them are heterozygous.
Genotypes (phenotype) 25% homozygous dominant (free earlobes) 25% homozygous recessive (attached earlobes) 50% heterozygous (free earlobes) 75% phenotypically dominant (free earlobes) 25% phenotyically recessive (attached earlobes) Ratios Genotype 1:1:2 Phenotype 3:1
50%. Heterozygous means that there is two different traits inside of the gene. Therefore you have (aa) for the free earlobes and the other individual with attached (Aa). Drawing a Punnett square you get (aa) in two different spots, creating 50% probability.
He has at least one E allele is correct. I take the quiz
He has a homozygous genotype
If both you and your sibling have attached earlobes (aa genotype) and your parents have unattached earlobes, then your parents must both be carriers of the recessive allele for attached earlobes (Aa genotype).
The phenotypes of attached and unattached earlobes do not fit neatly into the Mendelian theory of two alleles for one trait, and there is a continuum of earlobe phenotypes. That said, unattached earlobes are a dominant trait, so if the individual is homozygous for unattached earlobes, all of her offspring will have the unattached phenotype, even if some or all of them are heterozygous.
If both parents are heterozygous for attached earlobes (genotype Ee, where E is the dominant allele for free earlobes and e is the recessive allele for attached earlobes), the possible genotypes for their child can be determined using a Punnett square. The possible combinations are EE, Ee, Ee, and ee. This means there is a 25% chance (1 out of 4) that the student will inherit the genotype ee, resulting in attached earlobes. Thus, there is a 25% likelihood that the student has attached earlobes.
Dominant. he has a homozygous genotype
Genotypes (phenotype) 25% homozygous dominant (free earlobes) 25% homozygous recessive (attached earlobes) 50% heterozygous (free earlobes) 75% phenotypically dominant (free earlobes) 25% phenotyically recessive (attached earlobes) Ratios Genotype 1:1:2 Phenotype 3:1
If your friend has attached earlobes (recessive trait), then your friend must have two copies of the recessive allele for attached earlobes (aa). This means that both of your friend's parents must be carriers of the recessive allele (Aa) in order to pass it on. Your friend's mother and father would both have one dominant allele (A) for free-hanging earlobes and one recessive allele (a) for attached earlobes.
The parents would each have the genotype Ee (heterozygous for earlobe attachment) and the phenotype for hanging earlobes. The child inherited the attached earlobe allele from both parents, resulting in the AA genotype and the phenotype for attached earlobes.
50%. Heterozygous means that there is two different traits inside of the gene. Therefore you have (aa) for the free earlobes and the other individual with attached (Aa). Drawing a Punnett square you get (aa) in two different spots, creating 50% probability.
Yes, it is possible for two individuals with attached earlobes (ee genotype) to have children with free earlobes. This would depend on the specific genotypes of the parents and the inheritance pattern of the earlobe trait, which is typically considered a simple Mendelian trait. If both parents carry hidden free earlobe genes (Ee), there is a chance that their children may have free earlobes.
He has at least one E allele is correct. I take the quiz
The genotype of the unaffected children can be 1 of 2 different things. The genotype can be either completely dominant or heterogeneous.