AA X aa
= 4 Aa
======the only possible cross between a true breeding homozygous dominant and a true breeding homozygous recessive.
The alleles of the f1 offspring will depend on the alleles of the parents. In theory all of the alleles in the parental genotypes could be present in the f1 generation.To work out which combinations of alleles will be present in the f1 generation/the proportion with one allele etc. you would need to draw some kind of cross.AA x AaA AA AA AAa aA aASo the f1 offspring have both the A and a alleles, because the two alleles from each parent are separated into the gametesAA gives two gametes both with 'A' alleleAa gives on gamete with 'A' and one with 'a'
In a BB x bb cross, all offspring will have the genotype Bb. The offspring will exhibit the dominant trait of the B allele.
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
In the cross BB x bb, all offspring in the F1 generation will have the genotype Bb, as they inherit one allele from each parent. None of the offspring will have the same genotype as either parent.
The males chromosomes determine the gender of the baby. Women have an XX chromosome and men have an XY chromosome. So women can only give an X chromosome, but men can give either/or.The chromosomes of the father make the final determination; the child either gets a X from the mother and either an X from the father which makes a girl, or an X from the mother and a Y from the father, which makes a boy.Jamiana:The Father's(it's Y though)
25%
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
And the boxes are how big ????
6 x 6 = 36 boxes
There are 9 boxes in a 3x3 grid.
80 eight boxes wide by ten boxes long
A dihybrid cross results in 16 boxes for the offspring. For example, the cross RrDd X RrDd is shown below:RDRdrDrdRDRRDDRRDdRrDDRrDdRdRRDdRRddRrDdRrddrDRrDDRrDdrrDDrrDdrdRrDdRrddrrDdrrdd
None - if the little boxes are taller than the big box!
That depends on the size of the little boxes. If they're all 1-cubic-foot boxes, then you can fit (7 x 7 x 8) = 392 of them in there. And by the way ... 7 x 7 x 8 is not a "cube".
17 x 13 = 221 221/23.97 = 9.22 9.22 boxes or 10 whole boxes.