How many gametes are formed by individual of genotype AaBbcc?

Answer 1

A faster way to do it is by (2^n) where 2 is the number of alleles and n is the number of genes, so we have 2^3 = 8. so we have 8 possible combinations.

Assuming you are asking how many different types of gametes can an individual with the genotype AaBbCc make. To answer we must first make one assumption: each gene resides on a different chromsome. The reason we do that is to simplify the analysis by making use of Mendel's Law of Independent Assortment. The possible genotypes in the gametes are thus:

ABC

ABc

AbC

Abc

aBC

aBc

abC

abc

Independent Assortment allows us to determine the answer by simply listing out all of the possible combinations of alleles. However, if all or some of the genes are on the same chromosome, the answer becomes much more difficult, because then one has to know the probability of recombination between the genes. The closer in physical proximity on the chromosome the genes are, the less probable recombination (crossing over) will occur between them, because it's more difficult for crossing over to happen on very short stretches of DNA.

Answer 2

ABc, aBc, abc, Abc. Four different gametes are formed by an individual with the genotype AaBbcc.