The Adenine (Thymine) base pair is held together by 2 hydrogen bonds while the Guanine (Cytosine) base pair is held together by 3 hydrogen bonds. That is also the reason why the two strands of a DNA molecule can be separated more easily at sections that are densely populated by A - T base pairs.
Adenine, Guanine and Cytosine are found in both RNA and DNA.DNA; A, T, G and CRNA; A, U, G and C
Adenine, Thymine, Cytosine, GuanineA base pairs with TC base pairs with G
Hydrogen bonds are one of the weakest bonds, and aren't even true bonding of molecules, but rather a magnetic attraction between them. This particular bond is what allows the base pairs of DNA to properly link, as Adenine and thymine bond, and cytosine and guanine bond, but neither of these pairs bonds with elements from the other pair in this way.
Hydrogen bonds between adenine and thymine and between cytosine and guanine.
Guanine to Cytosine in DNA Via a triple hydrogen bond for example NH2 donor group bonds to the =O acceptor group on G? Similarly, the two donor groups on G (NH and NH2) match the acceptor groups on C The NH2 at the top of A would clash with the NH2 on C. You can't form an H-bond with two donor groups and no acceptor. Those two groups would actually get in each other's way, forcing the helix to distort. Also, A has no H-bond donors in the middle or at the bottom. So A and C can't pair. T and C have a different problem. The top and middle groups of T could potentially h-bond with the complementary groups on C. But the helix would hold T and C too far apart. (The connection between each base and the backbone is the wavy line.) H-bonds can't form if the groups are to far apart from each other. So this is why G and C have to be pared together
Adenine, Guanine and Cytosine are found in both RNA and DNA.DNA; A, T, G and CRNA; A, U, G and C
Complementary nitrogen bases pair by means of hydrogen bonds. Refer to the related link below for an illustration.
Hydrogen bonds hold the DNA bases together. There are three bonds between Guanine and Cytosine, and two bonds between Adenine and Thymine.
The four different nucleotides have different strucutres: Adenine and Guanine have 2 ring structures. However, Cytosine and Thymine have singular ring structures. This means that Adenine cannot pair with Guanine as the two ring structures will be bigger than the singular ringed structure and the two strands of DNA are equidistant the entire length. Adenine and Thymine both have the ability to form 2 hydrogen bonds, whereas Cytosine and Guanine form 3 hydrogen bonds. Therefore Adenine and Thymine bond together, Cytosine and Guanine bond together. These hydrogen bonds between four different types of nucleotides (due to 4 different nitrogenous bases) hold together the two strands of DNA to form a double strand of DNA.
Adenine, Thymine, Cytosine, GuanineA base pairs with TC base pairs with G
Hydrogen bonds are one of the weakest bonds, and aren't even true bonding of molecules, but rather a magnetic attraction between them. This particular bond is what allows the base pairs of DNA to properly link, as Adenine and thymine bond, and cytosine and guanine bond, but neither of these pairs bonds with elements from the other pair in this way.
Hydrogen bonds (two between adenine and thymine, and three between guanine and cytosine).
Adenine and Thymine Guanine and Cytosine held together by hydrogen bonds: 2 for A-T and 3 for G-C
They pair by hydrogen bonds holding them together. Covalent bonds hold the nucleotides together, creating a sugar-phosphate backbone.
Hydrogen bonds between adenine and thymine and between cytosine and guanine.
Pyrimidines are the single ringed structures-Cytosine and ThyminePurines are the double ringed structures- Adenine and Guanine.
Guanine to Cytosine in DNA Via a triple hydrogen bond for example NH2 donor group bonds to the =O acceptor group on G? Similarly, the two donor groups on G (NH and NH2) match the acceptor groups on C The NH2 at the top of A would clash with the NH2 on C. You can't form an H-bond with two donor groups and no acceptor. Those two groups would actually get in each other's way, forcing the helix to distort. Also, A has no H-bond donors in the middle or at the bottom. So A and C can't pair. T and C have a different problem. The top and middle groups of T could potentially h-bond with the complementary groups on C. But the helix would hold T and C too far apart. (The connection between each base and the backbone is the wavy line.) H-bonds can't form if the groups are to far apart from each other. So this is why G and C have to be pared together