All the F1 will have wire hair.
The reason:A homozygous wire-haired dog must be SS. It must have at least one S allele if it shows the dominant character, and "homozygous" means pure-breeding, so there is no other allele present.
A smooth-haired dog must be ss. Any organism displaying a recessive trait must be homozygous, as a dominant allele would mask the recessive one.
So the cross is:
SS x ss
and one parent must pass on the S gene, one the s. Therefore all the F1 must be Ss. Their phenotype is wire-haired, because they have a dominant allele, but they are all heterozygous, because they inherited a recessive gene from the smooth-haired parent.
This cross demonstrates Mendel's First Law.
What is the genotype and phenotype of the F1 generation
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.
You would expect 1 homozygous dominant, 2 heterozygous dominant and 1 homozygous recessive offspring. This is because each parent has one dominant and one recessive allele. Therefore there is a 75% chance of a dominant phenotype and a 25% chance of a recessive phenotype.
To determine the genotype of an individual that shows the dominant phenotype you would cross that individual with one that is homozygous recessive. A monohybrid cross of two individuals that are heterozygous for a trait exhibiting complete dominance would probably result in a phenotype ratio is 3 dominant 1 recessive.
What is the genotype and phenotype of the F1 generation
All of the F1 generation are heterozygous, therefore 100% exhibit the dominant phenotype. The F2 generation has a ratio of 1 homozygous dominant: 2 heterozygous: 1 homozygous recessive. This results in a phenotypic ratio of 3 dominant: 1 recessive.
All of the F1 generation are heterozygous, therefore 100% exhibit the dominant phenotype. The F2 generation has a ratio of 1 homozygous dominant: 2 heterozygous: 1 homozygous recessive. This results in a phenotypic ratio of 3 dominant: 1 recessive.
homozygous dominant is the genotype. hypothetically, if the gene was for the color purple in a flower, the phenotype would be purple, while the genotype would be homozygous dominant AKA Pp.
The same phenotype as both of the parents.
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
Straight thumbs, hitch hiker's thumb is recessive...so the F1 generation in this example would be heterozygous and have the dominant (straight thumbed) phenotype.
The phenotype (as I assume would be colour) for both homozygous and heterozygous yellow-grained corn is yellow.
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.
Homozygous dominant and heterozygous both are a dominant phenotype.
It's expressed when a heterozygous phenotype is between two homozygous phenotypes.