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Round seeds are dominate to wrinkled seeds What percentage of the offspring will be round?
If round seeds are dominant and wrinkled seeds are recessive, then in a cross between two plants with heterozygous genotypes (Rr), 75% of the offspring will have round seeds (25% RR, 50% Rr) and 25% will have wrinkled seeds (rr).
What is the genetic nature of wrinkled phenotype of pea seeds?
The wrinkled phenotype of pea seeds is due to a mutation in the gene that encodes for the starch-branching enzyme known as SBEI. This mutation causes a deficiency in the enzyme, resulting in the accumulation of unbranched starch in the seeds, which leads to the wrinkled appearance.
Round seed shape in peas is an example of a trait controlled by a dominant allele beacause?
Round seed shape in peas is an example of a trait controlled by a dominant allele because the presence of even one copy of the dominant allele results in the expression of the round seed shape phenotype. This means that individuals with either two dominant alleles (RR) or one dominant and one recessive allele (Rr) will have round seeds, while individuals with two recessive alleles (rr) will have wrinkled seeds.
What was the dominant alleles in Mendel's pea plants?
The dominant alleles in Mendel's pea plants were those responsible for the traits of round seeds (R) versus wrinkled seeds (r), yellow seeds (Y) versus green seeds (y), purple flowers (P) versus white flowers (p), and inflated pods (I) versus constricted pods (i).
When Mendel allowed heterozygous F1 plants that had round yellow seed to self-pollinate he found that some of the F2 plants had wrinkled green seeds is this true or false?
False. When Mendel allowed heterozygous F1 plants with round yellow seeds to self-pollinate, he found that the F2 generation followed the expected 9:3:3:1 phenotypic ratio. This means that all possible combinations of seed shape (round or wrinkled) and seed color (yellow or green) were observed in the F2 generation in the ratio of 9 round yellow: 3 round green: 3 wrinkled yellow: 1 wrinkled green.
Round seeds are dominate to wrinkled seeds What percentage of the offspring will be round?
If round seeds are dominant and wrinkled seeds are recessive, then in a cross between two plants with heterozygous genotypes (Rr), 75% of the offspring will have round seeds (25% RR, 50% Rr) and 25% will have wrinkled seeds (rr).
How did gregor mendel make sure that the plants with round seeds did not self pollinate?
He allowed plants whose seeds were round or wrinkled in shape to self pollinate. This trait has two variations-either round or wrinkled seeds.
Two forms of the traits of seed shape in pea plants are?
Mendel described two seed shapes among the pea seeds in his study: Smooth and Wrinkled.
What is the probability that a offspring will have wrinkled seeds?
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
Suppose that in a pea plant round seeds are dominant over wrinkled seeds in the and ldquotexture and rdquo gene. If you were to take two plants heterozygous for the texture gene and cross them togethe?
Suppose that, in a pea plant, round seeds are dominant over wrinkled seeds in the "texture" gene. If you were to take two plants heterozygous for the texture gene and cross them together to make eight new plants, how many of those plants should express the smooth phenotype? Use a Punnett's Square to determine the results.
What is the genotype for a hybrid round pure yellow pea?
In pea plants, round seeds are dominant (R) over wrinkled seeds (r), and yellow seeds are also dominant (Y) over green seeds (y). A hybrid round pure yellow pea would have the genotype RrYY, where "Rr" indicates it is heterozygous for the round seed trait and "YY" indicates it is homozygous for the yellow seed trait.
How did Mendel make sure that the plant with round seeds did not self pollinate?
He allowed plants whose seeds were round or wrinkled in shape to self pollinate. This trait has two variations-either round or wrinkled seeds.
How did Gregor Mendel make sure that the plant with round seeds did not self pollinate?
He allowed plants whose seeds were round or wrinkled in shape to self pollinate. This trait has two variations-either round or wrinkled seeds.
What is the possibility that two heterozygous parents would have an offspring that produced round seeds?
In pea plants, the round seed trait (R) is dominant over the wrinkled seed trait (r). If both parents are heterozygous (Rr), the possible offspring genotypes are RR, Rr, and rr, with a 75% chance of producing round seeds (RR or Rr) and a 25% chance of producing wrinkled seeds (rr). Therefore, there is a 75% possibility that two heterozygous parents would have an offspring that produces round seeds.
What is the genetic nature of wrinkled phenotype of pea seeds?
The wrinkled phenotype of pea seeds is due to a mutation in the gene that encodes for the starch-branching enzyme known as SBEI. This mutation causes a deficiency in the enzyme, resulting in the accumulation of unbranched starch in the seeds, which leads to the wrinkled appearance.
How did the results of mendels dihybrid crosses lead him to formulate the law of independent assortment?
It helps if you know how to set up the problem in a Punnett square and look at the results. For now, let's just say that for a dihybrid cross is between a plant with green, wrinkled seeds and one with yellow round seeds. The traits of green (G) is dominant over yellow(g) and round (R) is dominant over wrinkled (r). If the traits were "connected" then the offspring should be one or the other of the parental types. But in reality, you'll get plants with green, smooth seeds as well, since a plant with one "R" allele is all that's necessary to produce a plant with the dominant round seeds. And if the cross was between two heterozygous plants (GgRr x GgRr all with the phenotype of green round seeds), the offspring will be a mix of plants with a ratio of 9 green and round to 3 green and wrinkled, to 3 yellow and smooth, to 1 yellow and wrinkled. So if 1600 offspring were produced, there would be approximately 900 with both characteristics showing the dominant phenotype, 300 wit just one trait being dominant, 300 with the opposite trait being dominant, and 100 with neither dominant characteristic instead of all being the dominant characteristics like the parents. Or 50/50. So this shows that the chromosomes that carry these characteristics are independent of each other.
How did the results of Mendels dihybrid cross lead him to formulate the law of independent assortment?
It helps if you know how to set up the problem in a Punnett square and look at the results. For now, let's just say that for a dihybrid cross is between a plant with green, wrinkled seeds and one with yellow round seeds. The traits of green (G) is dominant over yellow(g) and round (R) is dominant over wrinkled (r). If the traits were "connected" then the offspring should be one or the other of the parental types. But in reality, you'll get plants with green, smooth seeds as well, since a plant with one "R" allele is all that's necessary to produce a plant with the dominant round seeds. And if the cross was between two heterozygous plants (GgRr x GgRr all with the phenotype of green round seeds), the offspring will be a mix of plants with a ratio of 9 green and round to 3 green and wrinkled, to 3 yellow and smooth, to 1 yellow and wrinkled. So if 1600 offspring were produced, there would be approximately 900 with both characteristics showing the dominant phenotype, 300 wit just one trait being dominant, 300 with the opposite trait being dominant, and 100 with neither dominant characteristic instead of all being the dominant characteristics like the parents. Or 50/50. So this shows that the chromosomes that carry these characteristics are independent of each other.
