If one fruit fly is heterozygous for long wings and the other is homozygous for short wings, the expected percentage of their offspring having long wings would be 50%. This is because when the long-winged parent passes on the dominant long-wing allele and the short-winged parent passes on the recessive short-wing allele, the offspring would have one of each allele, resulting in the offspring having long wings.
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
1:2:1, as incomplete dominance results in a blending of traits from two different alleles, producing an intermediate phenotype in heterozygous individuals. This ratio is characteristic of crosses involving incomplete dominance.
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
Here are a few practice problems to help you understand Hardy-Weinberg equilibrium: In a population of 500 individuals, 25 exhibit the recessive trait for a certain gene. What are the frequencies of the dominant and recessive alleles in the population? If the frequency of the homozygous dominant genotype in a population is 0.36, what is the frequency of the heterozygous genotype? In a population of 1000 individuals, 64 exhibit the dominant trait for a certain gene. What are the expected frequencies of the three genotypes (homozygous dominant, heterozygous, homozygous recessive) in the population? Try solving these problems using the Hardy-Weinberg equations and principles!
Rr
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.
The expected genotypic ratio differs from the expected phenotypic ratio because genotypes represent the actual genetic combinations (e.g., homozygous dominant, heterozygous, homozygous recessive), while phenotypes reflect the observable traits resulting from those genotypes. In cases where one allele is dominant over another, multiple genotypes can lead to the same phenotype. For example, in a monohybrid cross, the expected genotypic ratio might be 1:2:1 for the alleles, while the phenotypic ratio could be 3:1, as both homozygous dominant and heterozygous individuals display the same dominant phenotype.
That depends on which color is dominant. If red is dominant, then F1 will all be red heterozygous. If orange is dominant, then same applies.
If one trait is dominant over the other, then the resulting F1 generation would be expected to have the heterozygous genotype and dominant phenotype.
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
Fyugugy
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
1:2:1, as incomplete dominance results in a blending of traits from two different alleles, producing an intermediate phenotype in heterozygous individuals. This ratio is characteristic of crosses involving incomplete dominance.
If a normal heterozygous dog (Dd) is crossed with another normal heterozygous dog (Dd), the Punnett square shows the possible genotypes of the offspring: DD, Dd, Dd, and dd. This results in 25% DD, 50% Dd, and 25% dd. Therefore, 25% of the offspring would be expected to be deaf (dd).
To determine the number of wondercorn offspring from a heterozygous cross, we need to know the inheritance pattern and the ratio of offspring phenotypes. Assuming wondercorn is a dominant trait and the cross is between two heterozygous individuals (e.g., Aa x Aa), the expected phenotypic ratio would be 3:1 (dominant to recessive). Therefore, out of 736 offspring, approximately 552 would be wondercorn (3/4 of 736).