0
Two individuals heterozygous for a single trait have children what is the expected phenotypic ratio of the possible offspring?
Let T=trait (dominant)
Let t= trait (recessive)
Father has Tt
and mother also has Tt
The possible combinations for offspring are: TT Tt Tt and tt
Therefore
There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait
It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
What else can I help you with?
What can you predict about the offspring if you know the genotypes of the parents?
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
Can drawfs or midgets reproduce?
Yes, individuals with dwarfism can reproduce just like individuals without dwarfism. The likelihood of passing on the condition to their offspring can vary depending on the specific genetic cause of the dwarfism. It is possible for individuals with dwarfism to have children who do not have the condition.
What is a X linked carrier homozygous?
An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.
If a heterozygous male mates with an albino female what percentage of children will be albino?
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.
What does it mean to be heterozygous for a trait?
One cannot really be heterozygous for a trait. You can be heterozygous for a gene, and based on the whether that gene is dominant or recessive will determine if you express that trait or not. Humans (and most organisms) carry two copies of each chromosome. As such, for a given genetic sequence, there can be three possibilities (there are exceptions, but let's keep it simple for now). The genes A)both code for the trait, B) neither code for the trait, or C) One gene does and the other does not. The C option is is being heterozygous. Let's get an example now: Assume that in some animal, there are only two hair colors -- Black or White. Also, the Black Hair color is Dominant. The black hair color is coded by the uppercase letter "B" and the white hair color is coded by the lowercase letter "b". An animal with the coding "BB" is HOMOZYGOUS for Black hair because BOTH genes code for black hair. Similarly, an animal coding "bb" will have White hair, because BOTH genes code for white hair. Now, let's say these two animals mate and have a baby coding with "Bb". This baby will have BLACK hair because the Black hair color is dominant and overpowers the White hair gene. To be Heterozygous (usually) means that you will express the dominant version of the trait, BUT your offspring/children can possibly get the recessive version of the trait.
Which pairs of individuals in the pedigree have children?
The pairs of individuals who have children in the pedigree are the ones connected by a horizontal line with offspring below them.
A man and a woman are both heterozygous Freckles are dominant over no freckles What are the chances their children will have freckles?
There is a 75% chance that their children will have freckles and a 25% chance that their children will not have freckles. This is because both parents are carriers of the freckles allele and can pass it on to their offspring.
What can you predict about the offspring if you know the genotypes of the parents?
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
In humans widow's peak (W) is dominant over straight hairline (w). If a heterozygous male marries a female with a straight hairline what percent of their children can be expected to have widow's peak?
50% of their children are expected to have a widow's peak. When a heterozygous male (Ww) with a widow's peak gene marries a female with a straight hairline (ww), their offspring have a 50% chance of inheriting the widow's peak gene from the father.
What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
A homologous tall man (TT) marries a heterozygous tall woman (Tt). if they have 12 children what will their children look like based on the result of Mendel's experiment (Phenotype)?
In this cross between a homozygous tall man (TT) and a heterozygous tall woman (Tt), all offspring will inherit at least one dominant tall allele (T) from the father. Therefore, the possible genotypes of their children are either TT or Tt. As a result, 100% of their children will exhibit the tall phenotype based on Mendel's principles of inheritance.
If children with blood group O and a what could be the blood group of parents?
both parents could be A heterozygous or one A heterozygous and the other O
What is the synonym for offspring?
Children
Would Squidward's children still be considered purebreds explain please?
No, Squidward's children would not be considered purebreds because the term "purebred" refers to offspring with parents of the same breed (in this case, squids). As Squidward is a sea creature in a fictional animated series, the concept of purebreds does not apply.
Which is the dominant gene father has dark brown eyes mother has blue eyes?
Sure you don't mean heterozygous dominant? If you don't there would be no blue eyed offspring. Let's assume you meant heterozygous dominant.B = brownbl = blueBbl X Bbl1/4 of the offspring would have blue eyes, 25%.
Will parents with a positive blood type have children with a positive blood type?
There is 50% that children will be of negative blood type if parents are heterozygous positive. 25% if one parent is homozygous and other heterozygous. 0% if both homozygous.
Can drawfs or midgets reproduce?
Yes, individuals with dwarfism can reproduce just like individuals without dwarfism. The likelihood of passing on the condition to their offspring can vary depending on the specific genetic cause of the dwarfism. It is possible for individuals with dwarfism to have children who do not have the condition.
