Basically, they are formed by replacing one or more H atoms in the organic molecule. The number of H atoms forms the types of the alkyl halides....It's a very vast topic for 12th and it can even kill you...
The compounds formed by the replacement of one or more hydrogen atoms of alkanes by halogen atoms are called halogen derivatives of alkanes. Examples: CH3Cl (methyl chloride), C2H5 Br (ethyl bromide)
halogen derivatives of alkanes are carbon compounds in which hydrogen atom is replaced by equal number of halogen atoms like f,cl,Br.I
chemical equation for halogenation
They are called halogenides.
Agar (a seaweed derivative)
Thymine is a pyrimadine base. Guanine is a purine derivative.
Iodine is a nonmetallic crystaline element in the halogen family, not a plant.
halo alkane or alkyl halides
An alkane. Hence the name alkyl. An alkane is a chain of carbon atoms bonded to each other with single bonds, with hydrogen atoms filling the remainder of the bonds. One hydrogen atom is replaced by a halogen to form an alkyl halide.
its just a Alkane with a halogen in the place of one or more hydrogens. ex) 1-bromopropane, Br-CH2CH3
No, ethane is an alkane, which is a type of hydrocarbon. Halogens on the other hand are elements in group 7 of the periodic table.
Pn x is the penicillin derivative containing halogen carbonyl group hence 'x' may stand for the halogen
no, chloroethene is not an alkane as all alkanes end with an -ane so chloroethene will be an alkene as it ends with -ene.
When a metal reacts with a haloalkane it forms an organometallic reagent such as Alkyllithium (RLi) or the Grignard Reagent (RMgX) where R is an alkane and X is a halogen.
Any number of chemical moieties could react with alkanes to produce new compounds in a substitution reaction. For example, hydrohalic acids (HCl, HBr, HI) could react with an alkane to produce a haloalkane. Here, the halogen atom would replace one of the hydrogen atoms in the alkane. (HCl + ethane --> chloroethane) (HBr + propane --> bromopropane) This also works with other reactive species, such as: - nitric acid + alkane --> nitroalkane
You get an Anti Markovnikov addition to an alkane. The bromide ends up on the less substituted carbon in this instance. Br is the only halogen that is effected by H202. If you were to add HCL and H202 to an alkane, the Cl would attatch to the most heavily substituted carbon (follows Markovnikov).
Williamson Ether Synthesis: First the halogen will dissociate from the alkane leaving a carbocation. Then an alcohol (lone pairs of the oxygen) will attack the charged carbon to form an ether with a hydrogen attached to the (positively charged) oxygen. This readily dissociates (for example it can be removed by the halogen ion) to form the ether.
Alkane molecules are nonpolar.