Phenotype is the observed trait. The dominant trait in this case is observed- D
In this case, the mother does not have dimples (Dd) but the father does not have dimples (dd). The Punnett square would show that half of the offspring would have dimples (Dd) and the other half would not have dimples (dd).
The genotype of a heterozygous tall plant would be Tt, with one allele for tallness (T) and one allele for shortness (t).
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.
A CC genotype is homozygous, meaning both alleles at that gene locus are the same (in this case, both are "C"). In contrast, a heterozygous genotype would be represented as Cc, indicating two different alleles at that gene locus.
We can call these alleles. Each of us has two ABO blood type alleles, because we each inherit one blood type allele from our biological mother and one from our biological father.
Dd is the heterozygous genotype for dimples.
In this case, the mother does not have dimples (Dd) but the father does not have dimples (dd). The Punnett square would show that half of the offspring would have dimples (Dd) and the other half would not have dimples (dd).
Dd
There is not really enough information in the question to answer it properly. You would need to know what trait the D and d stood for to give a proper answer.If the dog's genotype is Dd and it has the disease, this suggests that the disease is caused by a dominant allele. A healthy bitch would have the genotype dd and half of her pups would have the disease. There is no mate which would produce all heathly pups.If the dog is symptom free then the disease is caused by a recessive allele. In which case the dog should be matted with a dog with the genotype DD to have 100% symptom free pups. Mating Dd to Dd would give 75% symptom free pups and 25% sufferers. Mating the Dd dog to a dd dog would give 50% disease free pups and 50% sufferers.
homozygous first filial organism,which can undergo mutation or which may be cross-linked or made to breed with other.
If the gene for a trait has two alleles, one dominant (D) and one recessive (d) there are three possible combinations in the genotype: DD (homozygous dominant) Dd (heterozygous) dd (homozygous recessive)
Assuming the dystonia is hereditary and is a recessive gene which will be called "d" for simplicity, that means the man must be "dd" and the woman is "Dd". This is the only way they could have a child who is "dd" like the father, but not the mother.
Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.
A dominant genotype is represented as DD or Dd but with many different letters. The DD is a homozygous dominant, while the Dd is the heterozygous dominant. Recessive is always represented as dd or rr or whatever letter you want to use. It is always homozygous recessive. There can never be a heterozygous recessive.
The genotype of a heterozygous tall plant would be Tt, with one allele for tallness (T) and one allele for shortness (t).
There are many types of dwarfism. If D is the autosomal dominant gene for acondroplasia a Dd heterozyote will be an acondroplastic dwarf. The homozygous DD individual dies shortly after birth due to considerable skeletal anomalies.
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.