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What are the genotypes of offspring from an FF X ff cross?

The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.


Freckles are a dominant characteristic The appearance of freckles is the phenotype what represents a heterozygous genotype for freckles?

If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.


In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?

There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur


If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?

Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.


The allelic make up of an individual is referred to as its?

I think it's genotype...

Related Questions

What is the child's genotype if parents both have normal arches produce a child with flat feet?

Child's genotype would be homozygous recessive alleles (nn) and parents would both have heterozygous dominant alleles (Nn).


What is the probability that an offspring mouse will be born with the genotype ff ee?

To determine the probability of an offspring mouse being born with the genotype ff ee, you need to know the genotypes of the parent mice. If both parents are heterozygous (Ff Ee), the probability of producing ff offspring is 1/4 and for ee offspring is also 1/4. To find the probability of the combined genotype ff ee, you multiply these probabilities: (1/4) x (1/4) = 1/16. Thus, there is a 1/16 probability that an offspring mouse will have the genotype ff ee, assuming both parents are Ff Ee.


What are the genotypes of offspring from an FF X ff cross?

The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.


What is genotype hybrids?

Mm, Ff, Gg, Ll, Ss and ect


Having freckles is dominant (F), and not having freckles is recessive (f). A mother has Ff and a father has ff. If they have a child, which genotype will make their child not have freckles?

ff (apex)


Having freckles is dominant (F) and not having freckles is recessive (f). A mother has Ff and a father has ff. If they have a child which genotype will make their child not have freckles?

ff (apex)


Is genotypes TT or ff a purebred?

Yes, a genotype of TT or ff indicates a purebred individual for a specific trait. TT signifies homozygous dominant, while ff signifies homozygous recessive.


Freckles are a dominant characteristic The appearance of freckles is the phenotype what represents a heterozygous genotype for freckles?

If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.


An AABbccDdEeFF individual is crossed with an individual with the genotype AaBBCCDdEeff what is the probability that their offspring will have the genotype AaBBCcddEEFf?

Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.


What are the Genotypes for free and fixed ear lobes in human beings?

The genotype for free ear lobes is usually represented as FF or Ff, where F stands for the dominant allele for free ear lobes. The genotype for fixed ear lobes is typically represented as ff, where f stands for the recessive allele for fixed ear lobes.


If the dominant allele F produces yellow flower color and re recessive allele f produces white flower color what are the possible pairs of alleles that would produce the yellow-flower phenotype?

The possible pairs of alleles that would produce the yellow-flower phenotype are FF and Ff. Since the F allele is dominant over f, having at least one F allele in the genotype will result in a yellow flower color.


In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?

There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur