recessive
The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
I think it's genotype...
Child's genotype would be homozygous recessive alleles (nn) and parents would both have heterozygous dominant alleles (Nn).
To determine the probability of an offspring mouse being born with the genotype ff ee, you need to know the genotypes of the parent mice. If both parents are heterozygous (Ff Ee), the probability of producing ff offspring is 1/4 and for ee offspring is also 1/4. To find the probability of the combined genotype ff ee, you multiply these probabilities: (1/4) x (1/4) = 1/16. Thus, there is a 1/16 probability that an offspring mouse will have the genotype ff ee, assuming both parents are Ff Ee.
The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.
Mm, Ff, Gg, Ll, Ss and ect
ff (apex)
ff (apex)
Yes, a genotype of TT or ff indicates a purebred individual for a specific trait. TT signifies homozygous dominant, while ff signifies homozygous recessive.
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.
The genotype for free ear lobes is usually represented as FF or Ff, where F stands for the dominant allele for free ear lobes. The genotype for fixed ear lobes is typically represented as ff, where f stands for the recessive allele for fixed ear lobes.
The possible pairs of alleles that would produce the yellow-flower phenotype are FF and Ff. Since the F allele is dominant over f, having at least one F allele in the genotype will result in a yellow flower color.
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur