white eye gene is ressecive, so the white eyed male is homocigous. You already knew that. So, wether the male apports either of his chromosome set, he will give the white eye gene in it. Now the heterocigous red eyed fly has the red eye gene (which is dominant), and the white eye gene (which is ressecive). But since the red eye gene is dominant, the fly has red eyes. Now, theorycally half the offspring would have white eyes, and the other half would have red eyes, because the male would always apport a white eye gene, cause he has a pair of white eyes genes; the female has a white eye gene and a red one. So, she will apport white gene half the times and red gene half the times, and half the offspring would be homocigote (white eye), and the other half would be heterocigote (red eye, since the red was dominant). To make it clear, lets call the white gene W, and the red one R. So the male set would be: (W, W) while the female would be (W, R), now combining them in all possibilities we have: (W, W), (W, R), (W, W), (W, R), as you can see, of four 2 are white eyed homocigotes and 2 red eyed heterocigotes. By the way, check that that is exactly what happens in humans about the sex, female being (X, X), and male being (X, Y), and so statistically we should have half the offspring being males and half of it being females. note: that applies only if the fly species is diploid, like humans. If drosophila melanogaster, which is the one you are talking about i think, isn't diploid, then it would be different from the above.
A heterozygous genotype (e.g. Aa) is not true-breeding because it carries two different alleles for a trait and can produce offspring with different genotypes when crossed. True-breeding genotypes are homozygous for a particular trait (e.g. AA or aa) and will consistently produce offspring with the same genotype when crossed.
In this case, the genotype of the white-eyed male fruit fly would be XwY, and the genotype of the heterozygous red-eyed female fruit fly would be XRXw. The expected ratio of genotypes in the offspring would be 1:1 for XRY (red-eyed males) and XRXw (red-eyed females).
If both oompahs are heterozygous (Oo), there are three possible genotypes that would result in offspring with orange faces: OO, Oo, and oO. Therefore, 75% of the offspring from this cross would have orange faces.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
The cross would result in a 1:1 ratio of white-eyed to red-eyed offspring. Half of the offspring would inherit the white-eyed trait from the white-eyed male, while the other half would inherit the red-eyed trait from the heterozygous red-eyed female.
You can find more information on inheritance on scienceprimer.com/x-linked-inheritance
A heterozygous genotype (e.g. Aa) is not true-breeding because it carries two different alleles for a trait and can produce offspring with different genotypes when crossed. True-breeding genotypes are homozygous for a particular trait (e.g. AA or aa) and will consistently produce offspring with the same genotype when crossed.
In this case, the genotype of the white-eyed male fruit fly would be XwY, and the genotype of the heterozygous red-eyed female fruit fly would be XRXw. The expected ratio of genotypes in the offspring would be 1:1 for XRY (red-eyed males) and XRXw (red-eyed females).
If both oompahs are heterozygous (Oo), there are three possible genotypes that would result in offspring with orange faces: OO, Oo, and oO. Therefore, 75% of the offspring from this cross would have orange faces.
Their offspring will be heterozygous recessive.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
The cross would result in a 1:1 ratio of white-eyed to red-eyed offspring. Half of the offspring would inherit the white-eyed trait from the white-eyed male, while the other half would inherit the red-eyed trait from the heterozygous red-eyed female.
Punnet square
In pea plants, the yellow color (Y) is typically dominant over the green color (y). If a heterozygous yellow pea plant (Yy) is crossed with a green pea plant (yy), the possible genotypes of the offspring would be 50% heterozygous yellow (Yy) and 50% homozygous green (yy). Therefore, the offspring would exhibit a 50% chance of being yellow and a 50% chance of being green.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
If the flowers are something like PP (purple) and pp (pink), then the flowers will be Pp if you do the traditional square used in most high school classes.
they are fine; expected ratios might not been seen simply due to chance