The expected phenotypic ratio resulting from a homozygous dominant individual mating with a homozygous recessive individual is 100% dominant phenotype in the offspring. This is because all the offspring will inherit at least one dominant allele from the homozygous dominant parent.
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
Here are a few practice problems to help you understand Hardy-Weinberg equilibrium: In a population of 500 individuals, 25 exhibit the recessive trait for a certain gene. What are the frequencies of the dominant and recessive alleles in the population? If the frequency of the homozygous dominant genotype in a population is 0.36, what is the frequency of the heterozygous genotype? In a population of 1000 individuals, 64 exhibit the dominant trait for a certain gene. What are the expected frequencies of the three genotypes (homozygous dominant, heterozygous, homozygous recessive) in the population? Try solving these problems using the Hardy-Weinberg equations and principles!
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
The phenotypic ratio of 2 hybrids would be 3:1 while the genotypic would be 1:2:1. ChaCha on!
In a monohybrid cross with one parent homozygous dominant and the other homozygous recessive The phenotype of the F1 offspring will be 100% that of the parent with the dominant allele. A cross of two of the F1 offspring will be 75% phenotypically like the dominant allele and 25% will be hommozygous recessive or 3 to 1
Rr
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.
The phenotypic ratio resulting from a dihybrid cross showing independent assortment is expected to be 9:3:3:1. This ratio is obtained when two heterozygous individuals are crossed for two traits that are independently inherited. The ratio represents the different combinations of phenotypes that can arise from the cross.
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
There is a 25% chance (1 in 4) that the offspring will be homozygous for the trait. This is because when both parents are heterozygous (Aa), they can pass on either the dominant allele (A) or the recessive allele (a) to their offspring, resulting in a 1 in 4 chance of the offspring receiving the recessive allele from both parents and becoming homozygous (aa) for that trait.
Here are a few practice problems to help you understand Hardy-Weinberg equilibrium: In a population of 500 individuals, 25 exhibit the recessive trait for a certain gene. What are the frequencies of the dominant and recessive alleles in the population? If the frequency of the homozygous dominant genotype in a population is 0.36, what is the frequency of the heterozygous genotype? In a population of 1000 individuals, 64 exhibit the dominant trait for a certain gene. What are the expected frequencies of the three genotypes (homozygous dominant, heterozygous, homozygous recessive) in the population? Try solving these problems using the Hardy-Weinberg equations and principles!
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.