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What is the mechanical advantage of a jack that is able to lift a 5000N car with 400N of effort?
The mechanical advantage of the jack is calculated by dividing the load force (5000N) by the effort force (400N). In this case, the mechanical advantage of the jack is 12.5, meaning that for every 1 unit of effort applied, the jack is able to lift 12.5 units of load.
Why does your Hp laser jet 5000n print an extra page with error undefined offending command stack?
a bear is called a bea , beer , bearrie
The pull of the engine is 5000 N When the wagon's speed is increasing how large is the friction force?
The question does not have enough information for a single answer. All we can tell from the question as is is that the friciton force must be less than 5000N. To give a definite number to the magnitude of the friction force we need to know at what rate the wagon is accelerating when the pull is 5000N.
How many pounds of pressure does it take to break a jaw?
It takes 8 pounds of pressure per square inch to break somebody's jaw.
A 8000 kg engine pulls a train of 5 wagons each of 2000 kg along a horizontal track if the engine exerts a force of 40000N and the track offers friction force of 5000N then calculate 1 the net acclera?
The net force acting on the train is the difference between the force exerted by the engine and the force of friction. Therefore, the net force is 40000N - 5000N = 35000N. To calculate the acceleration, we use the formula F = ma, where F is the net force, m is the total mass of the train, and a is the acceleration. Rearranging the formula to find acceleration, we get a = F/m. Plugging in the values, we get a = 35000N / (8000kg + 5*2000kg) = 1.75 m/s^2.
What effect does friction has on motion of object?
Friction is one of the many various types of retardant forces that resist motion. To the point, friction reduces the net force in a direction by acting in the opposite direction (effectively slowing it down). Take for example a car driving along the road. The car could be generating a force of say 5000 Newtons to the right and as a result of the tyres contacting the road surface, a frictional force of say 500N is generated to the left. This means that the net force is 4500N to the right. Take note then for this example if the frictional force was 5000N the car would be stationary.
How fast would a 1500 kg car be going if there was 5000N of force acting on it for 100m?
where, F = force, a = acceleration, vi = velocity initial, xf = position final, xi = position initial.F = ma5000 = 1500(a)a = 5000/1500 = 3.33 m/s^2v^2 = vi^2 +2a[xf - xi]assuming it started from rest, we havev = [0+2(3.33)(100-0)]^.5v = 25.8 m/s
A car of mass 1200 kg is travelling along a straight horizontal road with an accelaration of 3ms-2 The driving force of the engine is 5000N What is the magnitude of the resistance to motion?
The net force acting on the car can be calculated using Newton's second law: Fnet = ma. Given the acceleration of 3 m/s^2 and mass of 1200 kg, the net force is 1200 kg * 3 m/s^2 = 3600 N. Therefore, the resistance to motion can be calculated by subtracting the force due to the engine from the net force: 3600 N - 5000 N = -1400 N. The magnitude of the resistance to motion is 1400 N.
What force keeps a bridge from breaking?
well im looking for that answer but havent quite found it but i got this.....The truss elements are subjected only to tensile and compressive loads, and thus are designed accordingly. Truss bridges are not intended to withstand the bending forces, and are best suitable for the straight alignments. A truss bridge is designed to endure extreme weights and also cover extended gaps.
What is the weight of a 57 kg person on earth?
On Earth, 65 kg of mass weighs 637.5 newtons (143.3 pounds). (both rounded)
