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David & Denise Serls

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#include <stdio.h> #include <string.h> #define N 100 #define PALINDROME 0 #define NONPALINDROME 1 /*Program that tells you whether what you enter is a palindrome or not*/ char pal[N]; //input line int i; //counter int k; //counter int tag; int flag = PALINDROME; /*flag=0 ->palindrome, flag =1 ->nonpalindrome*/ int main() { printf("Enter something: \n"); scanf("%s", pal); tag = strlen(pal); /*determine length of string*/ /* pointer running from the beginning and the end simultaneously looking for two characters that don't match */ /* initially assumed that string IS a palindrome */ /* the following for loop looks for inequality and flags the string as a non palindrome the moment two characters don't match */ for (i=0,k=tag-1; i=0; i++,k--) { if(pal[i] != pal[k]) { flag=NONPALINDROME; break; } } if(flag == PALINDROME) { printf("This is a palindrome\n"); } else { printf("This is NOT a palindrome\n"); } return 0; } #include <stdio.h> #include <string.h> #define N 100 #define PALINDROME 0 #define NONPALINDROME 1 /*Program that tells you whether what you enter is a palindrome or not*/ char pal[N]; //input line int i; //counter int k; //counter int tag; int flag = PALINDROME; /*flag=0 ->palindrome, flag =1 ->nonpalindrome*/ int main() { printf("Enter something: \n"); scanf("%s", pal); tag = strlen(pal); /*determine length of string*/ /* pointer running from the beginning and the end simultaneously looking for two characters that don't match */ /* initially assumed that string IS a palindrome */ /* the following for loop looks for inequality and flags the string as a non palindrome the moment two characters don't match */ for (i=0,k=tag-1; i=0; i++,k--) { if(pal[i] != pal[k]) { flag=NONPALINDROME; break; } } if(flag == PALINDROME) { printf("This is a palindrome\n"); } else { printf("This is NOT a palindrome\n"); } return 0; }


Who owns the kismet?

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