To determine how many degrees J will raise the temperature of g of water, we need to use the specific heat capacity formula: ( Q = mc\Delta T ), where ( Q ) is the heat added (in joules), ( m ) is the mass of the water (in grams), ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the change in temperature (in °C). Rearranging the formula gives ( \Delta T = \frac{Q}{mc} ). Without specific values for Q and g, we cannot calculate the exact change in temperature.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
Q=6*550*1.00q=3300
11 at the airport
hexagons work because each angle is 120 degress, as you say, and 3 times 120 equals 360 degrees. So three hexagons will surround a point with no 'space" left over. but the interior angle of a pentagon is108 degrees. three pentagons together only fill up 3 time 108, or 324 degrees. There is space left over. But four pentagons would overlap. so 3 is not enough and 4 is too many. Pentagons cannot surround a point the way hexagons do.
That will completely depend on how much water there is.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
To calculate the temperature change, divide the energy (340 J) by the mass of water (6.8 g) and the specific heat capacity of water (4.18 J/g°C). This will give you the temperature increase in degrees Celsius.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
It takes 180 BTUs to raise 1 pound of water from 32 degrees Fahrenheit to 212 degrees Fahrenheit to convert it completely into steam. This change in temperature includes heating the water from its freezing point to boiling point, then undergoing phase change from liquid to gas.
To raise 1 gram of water by 40 degrees Celsius, you need 40 calories. This is based on the specific heat capacity of water, which is approximately 1 calorie per gram per degree Celsius. Therefore, for a temperature increase of 40 degrees, you multiply 40 degrees by 1 calorie per gram.
It depends on what temperature is is at and how much water there is.
To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.
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