2 9/16"
1/8 " - 11/2".
For every vertical foot of pipe, take that and multiply it by .434.This equation will get within 1/2 -1/4 psi.
To determine how many gallons will flow through a 2-inch copper pipe at a specific psi, you need to consider factors such as the pressure (psi), the length of the pipe, and any fittings or obstructions. Generally, a 2-inch copper pipe can flow approximately 1,200 gallons per minute at 50 psi under ideal conditions. However, for a precise calculation, it's best to use flow rate formulas or consult hydraulic tables that account for the specific conditions of your system.
To calculate the weight (WT) of a pipe, you can use the formula: [ \text{Weight} = \text{Volume} \times \text{Density} ] First, determine the volume of the pipe using the formula for the volume of a cylinder: [ \text{Volume} = \pi \times \left( \frac{D^2 - d^2}{4} \right) \times L ] where ( D ) is the outer diameter, ( d ) is the inner diameter, and ( L ) is the length of the pipe. Finally, multiply the volume by the material's density (typically in pounds per cubic foot or kilograms per cubic meter) to find the total weight.
The isosceles triangle of least area that can be circumscribed about a circle of radius r turns out to be not just isosceles, but also equilateral. Each side has length 2r x ( 3 )0.5 . The area is r2 x (27)0.5 . Thanks are due to litotes for pointing out that the original answer did not actually answer the question ! tpm Since the equilateral triangle is also an isosceles triangle, we can say that at least area that can be circumscribed to a circle is the area of an equilateral triangle.If we are talking only for isosceles triangle where base has different length than two congruent sides, we can say that at least area circumscribed to a circle with radius r, is the area of an isosceles triangle whose base angles are very close to 60 degrees. Solution: Let say that the isosceles triangle ABC is circumscribed to a circle with radius r, where BA = BC. We know that the center of the circle inscribed to a triangle is the point of the intersection of the three angle bisectors of the triangle. Let draw these angle bisectors, and denote with D the point where the bisector drawn from the vertex, B, of the triangle, intersects the base AC. Since the triangle is an isosceles triangle, then BD bisects the base and it is perpendicular to the base. So that AD = DC, OD = r, and the triangles ADB and AOD are right triangles (O is the center of the circle). In the triangle ADB, we have:tan A = BD/AD, so that AD = BD/tan A In the triangle AOD, we have:tan A/2 = OD/AD, so that AD = r/tan A/2, and AC = 2r/tan A/2 Therefore,BD/tan A = r/tan A/2, andBD = (r tan A)/tan A/2 Area of triangle ABC = (1/2)(AC)(BD) = (1/2)(2r/ tan A/2)[(r tan A)/tan A/2] = (r2 tan A)/tan2 A/2 After we try different acute angles measure, we see that the smallest area would be: If the angle A= 60⁰,then the Area of the triangle ABC = r2 tan 60⁰/tan2 30⁰ ≈ 5.1961r2 If the angle A= 59.8⁰,then the Area of the triangle ABC = (r2 tan 59.8⁰)/tan2 29.9⁰ ≈ 5.1962r2
Viscosity of Cast Iron Pipe = 2.09*10^5 lb s/ft^2
1/2" - 2" depending on demand
yes you can do it but you have to use a cast iron cutter, or cicular saw with a carbon friccion to cut arround the pipe. But if the cast iron pipe in in the ground and it's not muveble,, it may break.. so you have to be carefull and when you finish cutting it you put a piace of ABS pipe 1/2 shorter in each side. In order to incert the hob conectors..
Can you calculate the ID of a pipe when you have the OD to be 10.75" and the wall thickness to be 0.5"Depends on what you know about it. If you have the outer diameter and you know the wall thickness, then ID = OD-2 x wall thickness
There is a rubber connector available that will connect the two. It is a short rubber tube the right size on each end held on with a hose clamp on each end.Sorry to inform you there is NO such thing as a 21/2" CAST IRON piping IDThere is 11/2" cast iron 2", 3," 4", 5" 6" , 8", 10",Galvanized pipe comes in 11/2", 2" 21/2" 3" and years ago 7"
Not sure what you mean by pressure fittings. Threaded fittings for steel pipe are pressure fittings. Steel pipe with a 3/4" O.D. is known as 1/2" I.P.S. (Iron Pipe Size) pipe.
wall thickness of pipe is (OD - ID) /2
(Pi*(Center of elbow - od/2)^2-(pi*(Center of elbow+od/2)^2)÷4)÷100000=0.221 Square Meter
You just do it. Big help I know. There really isn't a question in your question. You cut the old pipe out and replace it. There is a chain cutter available that has a series of cutting wheels in a chain that you tighten down against the pipe and it basically breaks the cast iron pipe cleanly. Use a rubber coupler to connect the cast iron stub with the PVC. This is a short piece of rubber tube the right size to fit the pipe you are working with and is held on with 2 hose clamps. Where the cast goes into the floor or wall, you can take out the last section of cast and insert the PVC into the flare on the piece in the wall or floor and seal it as you would a piece of cast. Without a specific question, that's about all I can help you with.
You can put up to a 2 inch pipe into a 4 inch. If you are putting 4 inch to 4 inch, either take out a section of the cast and put the PVC in or cut out a section and connect the PVC to the cast with rubber sleeves meant for this. You can use a saddle clamp for the 2 inch. It is a half round piece of PVC with a 2 inch connection in it. It is held on with two U bolts that go around the cast pipe. Put it where you need it and mark the 2 inch hole on the cast. Drill a series of 1/8 inch holes around this circle. when you get them all drilled, you can break out the plug. Try to keep it from falling into the cast pipe. Put the saddle clamp on and connect the PVC pipe as needed. Seal the saddle clamp to the cast pipe with plumbers putty.
1/8" - 10" threaded Cast Iron 11/2" - 15" Copper 1/16 - 10" These are the most common sizes
IPS simply means Iron Pipe Size. Piping is a general term used to describe any hollow, cylindrical carrier of liquids. Many piping materials are used to produce both pipe and tubing. Piping and tubing made of the same materials generally use different kinds of fittings. All piping made to the OD (Outside Diameter) of wrought iron pipe is referred to as being Iron Pipe Size, or IPS. The OD of most pipes is the controlling dimension in order to match with fittings. When the term OD or (Outside Diameter) is used, the dimension being referred to is always the actual diameter unless proceeded by the phrase "nominal". Nominal size is a term used for the comparative sizes of piping and tubing rather than the actual dimensions. Like 3/4″ or 1″. Nominal sizes of piping in sprinkler systems are not the actual sizes and are given in inches and fractions of an inch. For a given NPS (Nominal Pipe Size), the OD stays fixed and the wall thickness increases with schedule. For example, you go to the home improvement store to buy some sprinkler pipe and you find Schedule 40 and Class 200 sprinkler pipe available. Both pipes will have the same OD(Outside Diameter), but the Schedule 40 pipe will have a thicker inner wall than the Class 200. Schedule 80 pipe will be thicker than Schedule 40 pipe but will also have the same OD. The gray 1/2″ riser nipples you buy for sprinkler risers in flower areas are often Schedule 80 nipples. So even though IPS is somewhat of a dinosaur term, it is still used when referring to the pipe size of the PVC pipe you are buying at the home improvement store. What makes it even nicer is that the Schedule 40 fittings you buy will fit all of these pipes, because all that is changing is the pipe thickness and not the OD (Outside Diameter) of the pipe.