200 kg @ max load capacity of 85% = 306 Litres
The heating value of the LPG is about 46 MJ/kg.
The cost per kilogram of liquefied petroleum gas (LPG) can vary significantly based on factors such as geographic location, market demand, and global oil prices. As of recent data, the price typically ranges between $0.50 to $1.50 per kg, but it is advisable to check local suppliers for current rates and any applicable taxes or fees. Additionally, prices may fluctuate due to seasonal changes and economic conditions.
The specific gravity of gasoline is approximately 0.701150 kg/min * (m^3/0.70*10^3 kg) * (1000 L /m^3) * (1 min / 60s) = 27 L / s
Of course it depends on the target pressure and temperature, so I don't have an exact answer, but I can show you how to make a good guess can form the density of liquid propane and the ideal gas law. The density of the liquid material at average sea-level atmospheric pressure and at its boiling temperature I have looked up and found to be 582 kg/m3. The gas at 25 C and average sea-level atmospheric pressure has a density of (moles*Molecular weight)/Volume = (Pressure*molecular weight)/(ideal gas constant*absolute temperature). Pressure = 1 atmosphere Molecular weight = 0.0441 kg/mole Ideal gas constant = [0.00008206 M3 Atm / K] Absolute temperature = 298.15 (i.e., 25 C) or density = 1 Atm * 0.0441 kg/mole / (0.00008206 M3 Atm /K * 298.15 K) = 1.8025 Kg/M3 Literature seems to say 1.8324 Kg/M3 (which is the same as g/L). This is simply because the ideal gas law is only an approximation -- this gas is close to it liquefaction point, so it is showing some discrepancy from ideal behavior. The expansion Ratio to get to standard conditions is therefore close to 582/1.80, or ~320
Note: edited for correctness Assuming that you meant ppmw (parts per million by weight), and not ppmv (parts per million by volume); and also that you meant short tons (2000 lbs) and not metric tonnes (1000 kg): x /(500 tons * 2000 lbs/ton + x) = 6/1,000,000 Where x is the amount of odorant in pounds. Solving for x yields: x= 6.000036 lbs for a 6 ppmw (parts per million weight) concentration This shows we can neglect the amount of odorant added since it is insignificant (0.00036 lbs) in the total, and the equation reduces to: x/(500*2000) = 6x10-6 yielding: x=6 lbs for 6ppmw likewise: x=12.001 lbs of odorant for 12ppmw or x=12 lbs for the simple calculation. Important conversion: ppm/1x106= fraction in total
Burning 1 kg of LPG produces approximately 2.98 kg of CO2.
1 kg of LPG is equivalent to around 1.36 cubic meters of methane.
The exact conversion of 1 kg of LPG (liquefied petroleum gas) to liters can vary slightly based on the specific density of the LPG. On average, 1 kg of LPG is approximately equal to 1.96 liters of LPG.
1 kg of LPG gas is equivalent to approximately 1.74 liters of LPG gas, as LPG has a density of about 0.54 kg/liter.
10 000
1 kilogram of LPG is equivalent to approximately 1.96 normal cubic meters (Nm³) of LPG.
The volume of 1 kg of LPG gas is approximately 1.96 liters. Therefore, 14.3 kg of LPG gas would be equivalent to around 28.04 liters.
The density of LPG can vary, but typically it is around 0.54 kg/L. Therefore, there are approximately 0.54 kilograms in a liter of LPG.
The weight of 1 liter of LPG can vary depending on the specific type of LPG and its composition. On average, 1 liter of LPG weighs approximately 0.54 kg.
Approximately 25 cubic meters of air is required to burn 1 kg of LPG completely. This is based on the stoichiometric ratio for the combustion reaction of LPG with oxygen.
1 cubic meter of LPG is equivalent to approximately 540 kg.
The heating value of the LPG is about 46 MJ/kg.