1 mole of any substance has 6.022 x 1023 atoms or molecules of that substance
0.44 mole Pb (6.022 X 10^23/1 mole Pb) = 2.6 X 10^23 atoms of lead
1 mole of H weights 1.008 g 1 mole = 6.02 x 10^23 particles Mass of 1 atom = 1.008 g / 6.02 x 10^23 = 1.67 x 10^-24 g
mass of one mole of oxygen atom is 16 grams. atomic weight of any atom is equal to mass of 1 mol of that atom...
Approximately 2 / (6.022 x 1023) = 3.32 x 10-24 grams
the first inoization energy is 2372.3 kJ mol-1 there are 6.0221415 × 10^23 in a mole from avagadros number, devide the ionization energy for one mole by the number of atoms in a mole and you get the first ionization energy for one atom.
8.90 X 1023 lead atoms (1 mole Pb/6.022 X 1023)(207.2 grams/1 mole Pb) = 306 grams of lead =============
mole
0.44 mole Pb (6.022 X 10^23/1 mole Pb) = 2.6 X 10^23 atoms of lead
To find the number of moles, you need to divide the given mass (9.51 x 10^3 g) by the molar mass of Pb. The molar mass of lead (Pb) is approximately 207.2 g/mol. So, 9.51 x 10^3 g Pb is equivalent to about 45.9 moles of Pb.
Number of nitrogen atoms in 1 mole nitrogen dioxide? Nitrogen dioxide has 1 N atom and 2 O atoms. One mole of nitrogen dioxide has 1 mole of N atoms
291.25 grams of lead (1 mole Pb/207.2 grams)(6.022 X 10^23/1 mole Pb) = 8.4648 X 10^23 atoms of lead I think you meant to say atoms, not molecules, as that is not a molecular formula and looks a lot like the symbol for lead with a possessive mark and s.
If the Atomic Mass of an atom is x, then the mass of 1 mole of the atoms is x gram.
1 mole has 6,022 141 29(27)×1023 atoms.
40g
1 mole of H weights 1.008 g 1 mole = 6.02 x 10^23 particles Mass of 1 atom = 1.008 g / 6.02 x 10^23 = 1.67 x 10^-24 g
The molar mass of lead (Pb) is approximately 207.2 g/mol. To find the mass of 33.3 moles of lead, you would multiply the number of moles by the molar mass: 33.3 moles * 207.2 g/mol = approximately 6890.76 grams of lead.
mass of one mole of oxygen atom is 16 grams. atomic weight of any atom is equal to mass of 1 mol of that atom...