Eventually you are going to have to sit an exam in this - it may be better for you if you ask someone to explain the method.
Improved*- Any question that is asked on this website could be on an exam. Wikianswers is suppose to give ANSWERS, not personal opinions. And having any questions asked being on a an exam is none of your concern. If you dont know the answer just say you dont know.
Times the original concentration by the original volume, this will give you the amount of iron present in the sample.
This amount of iron is diluted (divided) into the final volume yeilding the final concentration.
As a quick check you can compare the answer to a common sence ratio of the initial and final volumes and concentrations in this case roughly 4 --> 50ml or 0.2 --> 0.004mg/ml. If your answer is in the same region you can be confident you are correct.
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
55 ml of a 4.05 M solution of KI solution contains 55*4.05=222.75 millimoles. 20.5 ml of the diluted solution contains 3.8g of KI,so no.of moles of KI=3.8/(mol.wt of KI=165.9) is 22.9 millimoles. molarity of final diluted solution=22.9/20.5=1.117M since the no. of moles of KI present in initial and final solution are same. let.V(in ml) be the final volume of diluted solution. 222.75/V=1.117 V=199.41 ml final volume =199.41 ml
The key formula for solving a dilution problem is M1V1=M2V2 (alternately, MAVA=MBVB) where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V. M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution). Plug in the three values you know to find the fourth value, which you are solving for. Ex. 750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2? Answer: (0.5M)x(.750L)=(MB)x(.750L+.250L) 0.375ML=(MB)x(1L) MB=0.375M
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
sent them to concentration camps and death camps
Yes
You need to add the 50ul stock solution to 1200ul of distilled water to produce 1250ul of solution with a concentration of 2ul per ml.
13.6% methanol solution.
No, he never visited the concentration camps. He did not deal with the Final Solution plan, that was mostly Himmler's work.
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
.48 = [OH-]
Hilter did not dicide what to do to the Jews so he took them to GETTO where then they where send to the Final place concentration camps