2 kg of hydrogen at 1.00794 g mol-1 is about 1984 mols.
2 kg of hydrogen at STP (0 C, 101.325 kPa) at 0.08988 g/L is about 22,253 L.
To produce 100.0 kg of methanol, you would need 50.0 kg of carbon monoxide and 150.0 kg of hydrogen. This is because the reaction to produce methanol from carbon monoxide and hydrogen has a 1:3 ratio.
This equation and finding the limiting reactant.2H2 + O2 -> 2H2O2 kg H2 (1000 g H/1 kg H)(1 mole H/2.016 grams)= 992 moles hydrogen16 kg O2 (1000 g/1 kg)(1 mole O2/32.0 grams)= 500 moles oxygenI suspect hydrogen limits. Let's see.992 mole H2 (1 mole O2/2 mole H2)= 496 moles O2You have just a bit more than this in oxygen, so enough and hydrogen limits. ( check by going the other way and see the hydrogen limits )So, hydrogen drives the reaction.2 kg H2 (1000 g/1 kg)(1 mole H2/ 2.016 g)(2 mole H2O/2 mole H2)(18.016 g/1 mole H2O)(1 kg/1000 g)= 17.87 kilograms water made=========================( you do the significant figures )
The elements in hydrogen peroxide are hydrogen and oxygen.
Yes, hydrogen-1 and hydrogen-2 are isotopes of hydrogen. They have the same number of protons but different numbers of neutrons, with hydrogen-1 (protium) having no neutrons and hydrogen-2 (deuterium) having one neutron.
The formula for 2 atoms of hydrogen and 2 atoms of oxygen is H2O2, which represents hydrogen peroxide.
To produce 100.0 kg of methanol, you would need 50.0 kg of carbon monoxide and 150.0 kg of hydrogen. This is because the reaction to produce methanol from carbon monoxide and hydrogen has a 1:3 ratio.
This equation and finding the limiting reactant.2H2 + O2 -> 2H2O2 kg H2 (1000 g H/1 kg H)(1 mole H/2.016 grams)= 992 moles hydrogen16 kg O2 (1000 g/1 kg)(1 mole O2/32.0 grams)= 500 moles oxygenI suspect hydrogen limits. Let's see.992 mole H2 (1 mole O2/2 mole H2)= 496 moles O2You have just a bit more than this in oxygen, so enough and hydrogen limits. ( check by going the other way and see the hydrogen limits )So, hydrogen drives the reaction.2 kg H2 (1000 g/1 kg)(1 mole H2/ 2.016 g)(2 mole H2O/2 mole H2)(18.016 g/1 mole H2O)(1 kg/1000 g)= 17.87 kilograms water made=========================( you do the significant figures )
Mass of 1 hydrogen atom = 1.67 × 10−27 kgMass of sun = 2 x 1030 kgSo the ratio of the mass of the sun to that of a H atom= (2 x 1030) / (1.67 × 10−27)= (2 / 1.67) x (1030 / 10−27)= 1.2 x 1057If the sun were entirely composed of H atoms, this would be the number of H atoms in the sun.
2 kg is more.
Hydrogen has one of the highest energy density values per mass. Its energy density is between 120 (33.333kWh) and 142 MJ/kg (39.444kWh). This means that for every 1 kg of mass of hydrogen, it has an energy value of 120-142 MJ. It is highly flammable, needing only a small amount of energy to ignite and burn. Hydrogen burns cleanly. When it is burned with oxygen, the only by products are heat and water.
To find 0.125 of 2 kg, you multiply 2 kg by 0.125. This calculation gives you 0.25 kg. Therefore, 0.125 of 2 kg is 0.25 kg.
Convert to the same units then a comparison can be made: 1 tonne = 1000 kg → 2 tonne = 2 × 1000 kg = 2000 kg 2000 < 3000 → 2000 kg < 3000 kg → 2 tonnes < 3000 kg 3000 kg is larger than 2 tonnes.
Ammonia-NH3 2N+3H2=2NH3 2moles of Nitrogen produced 2moles of Ammonia (2*14)g of Nitrogen produced (2*17)g of Ammonia 28g of Nitrogen produced 34g of Ammonia 34g of Ammonia is produced by 28g of Nitrogen 0.034kg of Ammonia is produced by 0.028kg of Nitrogen 91.3kg of Ammonia will be produced by 0.028*91.3/0.034 91.3kg of Ammonia will be produced by 75.19kg of Nitrogen FOR HYDROGEN: 3moles of H2 produces 2moles of NH3 (2*3)g H2 produces 2*17g NH3 6g hydrogen produces 34g ammonia 0.006kg hydrogen produces o.o34kg ammonia 91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia
There are approximately 0.907 kg of sugar in 2 lbs.
7 pound 50 1 kg = £2.50 2 kg = £5.00 3 kg = £7.50
3 kg
2 T (tonnes) = 2,000 Kg 1 T = 1,000 Kg and .. 1 kg = 0,001 T :)