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You need to know 3 out of 4 variables to calculate the unknown.
Formula:
V1*M1=V2*M2
In your question only V1 (=50 mL) and M2 (=0.24m) are known.
Eg. V2 (volume of added NaOH in mL) has to be determined (most probably your buret readings; I hope you still can find it back in your lab journal)
What else can I help you with?
What is the molarity of an naoh solution if 4.37ml is titrated by 11.1 ml of 0.0904 m hno3?
The balanced equation for the reaction is 1 mole of NaOH to 1 mole of HNO3. Using the titration data, you can calculate the moles of HNO3 used. From there, you can determine the moles of NaOH present in the 4.37 ml solution. Finally, dividing the moles of NaOH by the volume of the NaOH solution in liters will give you the molarity.
How do you prepare a 50 percent of NaOH solution?
To prepare a 50% NaOH solution, dissolve 50g of NaOH pellets in 50mL of distilled water. Slowly add more water while stirring until you reach the desired volume. Make sure to wear appropriate protective gear and handle NaOH with care due to its caustic nature.
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
What is the molarity of an hcl solution if 7ml hcl solution is titrated with 27.6ml of 0.170m of naoh solution?
The balanced chemical equation for the reaction is: HCl + NaOH -> NaCl + H2O. From the equation, it is a 1:1 mole ratio reaction. Therefore, the moles of HCl can be calculated from the volume and concentration of NaOH used in the titration. Then, use the moles of HCl and the volume of HCl solution used to calculate the molarity of the HCl solution.
What happened if some solution splashes out during the titration of NaOH?
If some solution splashes out during the titration of NaOH, it could result in a decrease in the volume of the solution being titrated. This can lead to an inaccurate reading of the amount of titrant used and affect the accuracy of the titration results. It is important to take precautions to prevent spills and maintain a consistent volume throughout the titration process.
What is the molarity of an naoh solution if 4.37ml is titrated by 11.1 ml of 0.0904 m hno3?
The balanced equation for the reaction is 1 mole of NaOH to 1 mole of HNO3. Using the titration data, you can calculate the moles of HNO3 used. From there, you can determine the moles of NaOH present in the 4.37 ml solution. Finally, dividing the moles of NaOH by the volume of the NaOH solution in liters will give you the molarity.
20ml of acetic acid is titrated with a solutuion of 0.15 m naoh if 35 ml of naoh are required to reach the equivalence point what is the concentration of the acetic acid solution?
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How do you prepare a 50 percent of NaOH solution?
To prepare a 50% NaOH solution, dissolve 50g of NaOH pellets in 50mL of distilled water. Slowly add more water while stirring until you reach the desired volume. Make sure to wear appropriate protective gear and handle NaOH with care due to its caustic nature.
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
What is the products when amidosulphuric acid is titrated with sodium hydroxide?
H3NO3S + NaOH → Na3NO3S + H2O
What is the molarity of an hcl solution if 7ml hcl solution is titrated with 27.6ml of 0.170m of naoh solution?
The balanced chemical equation for the reaction is: HCl + NaOH -> NaCl + H2O. From the equation, it is a 1:1 mole ratio reaction. Therefore, the moles of HCl can be calculated from the volume and concentration of NaOH used in the titration. Then, use the moles of HCl and the volume of HCl solution used to calculate the molarity of the HCl solution.
What happened if some solution splashes out during the titration of NaOH?
If some solution splashes out during the titration of NaOH, it could result in a decrease in the volume of the solution being titrated. This can lead to an inaccurate reading of the amount of titrant used and affect the accuracy of the titration results. It is important to take precautions to prevent spills and maintain a consistent volume throughout the titration process.
Would your calculated molarity of NaOH be too high too low or unaffected if you titrated to a dark pink color?
If you titrated to a dark pink color, it signifies that you have overshot the endpoint and added excessive NaOH. This would make your calculated molarity of NaOH too high due to the excess base added beyond the equivalence point, affecting the accuracy of the results.
What volume of Na-OH is required to flip the indicator from colorless to pink at the endpoint?
The exact volume of NaOH needed to change the indicator to pink will depend on the concentration of the NaOH solution and the amount of acid in the solution being titrated. This can be determined by titrating a known volume of acid with a NaOH solution until the color change occurs.
A solution containing 3.76 g naoh in 361 ml water is titrated with 491 ml hcl what is the concentration of hcl in the original solution?
Given that the amount of NaOH is known, and the volume of HCl required for titration can be measured, you can calculate the concentration of HCl by using the balanced chemical equation and stoichiometry. The concentration of HCl in the original solution can be determined by dividing the moles of NaOH used in the reaction by the volume of HCl used. This calculation will yield the molarity of HCl in the original solution.
How an exact of 0.1N solution of NaOH can be prepared?
To prepare a 0.1N solution of NaOH, dissolve 4g of NaOH pellets in enough distilled water to make 1 liter of solution. This will result in a solution with a concentration of 0.1N of NaOH.
Can we make 1N NaOH solution from 0.1N NaOH solution?
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
