Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
The density of pure sodium hydroxide (solid) is 2,13 g/cm3.
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
You must know the method and not just the answer. Think about this problem: What does 5% mean? It tells you that for every 100g (or ml) water, you must have 5g of NaOH. You have 235 ml water. Therefore you will have to use more NaOH. You can calculate this as follows: (235/100)*5= 11.75g NaOH
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
The pH of a 50% solution of sodium hydroxide (NaOH) and water would be around 13. Sodium hydroxide is a strong base, so when dissolved in water it will result in a highly alkaline solution with a high pH value.
You need 50 g of this drug.
The density of pure sodium hydroxide (solid) is 2,13 g/cm3.
90 ml of dextrose and 4.41 litres of water.
120liters
To prepare a 50 percent saturated solution, first determine the solute's solubility in the solvent at the given temperature. For example, if the solute's solubility is 100 grams per 100 mL of solvent, you would dissolve 50 grams of the solute in 100 mL of the solvent. Stir the mixture until the solute is fully dissolved, and if needed, adjust the volume of the solution to ensure it remains at 100 mL. Always label the solution with the concentration and date prepared.