You must know the method and not just the answer. Think about this problem: What does 5% mean? It tells you that for every 100g (or ml) water, you must have 5g of NaOH. You have 235 ml water. Therefore you will have to use more NaOH. You can calculate this as follows:
(235/100)*5= 11.75g NaOH
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
You need 50 g of this drug.
To make 50 ml of 0.15 M NaOH solution, you would need to dilute the 3.05 M NaOH solution. Using the formula M1V1 = M2V2, where M1 is the initial concentration (3.05 M), V1 is the volume of stock solution needed, M2 is the final concentration (0.15 M), and V2 is the final volume (50 ml), you can calculate the volume of the stock solution needed to achieve the desired concentration. After calculating, you would mix the calculated volume of the 3.05 M solution with water to reach a final volume of 50 ml.
To make a 10 percent solution, you would need to dilute the 50 percent solution by adding 4 ml of solvent to 1 ml of the 50 percent solution. This will result in a total volume of 5 ml with a 10 percent concentration.
To create a 50% chlorinated solution from the 60% and 40% solutions, the chemist will need to mix the two in equal amounts. Therefore, 50 L of the 60% solution and 50 L of the 40% solution are needed to make a 100 L solution that is 50% chlorinated.
To prepare a 50% NaOH solution, dissolve 50g of NaOH pellets in 50mL of distilled water. Slowly add more water while stirring until you reach the desired volume. Make sure to wear appropriate protective gear and handle NaOH with care due to its caustic nature.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
First you must either know how much 50% NaOH you want to start with or know how much 2% NaOH you need at the end. Let's say you want 1L of the 2% NaOH. Use this equation, and solve for x, where in this case, x is the volume of 50% NaOH needed. (50% NaOH)x = (2%) * 1000 ml 0.5x = 0.02(1000) x = 20/0.5 = 40 Therefore, 40 ml of 50% NaOH in 960 ml water will produce 2% NaOH. Use a 1000 ml volumetric flask to be most precise.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
To prepare 100 ml of a 5% dextrose solution from a 50% dextrose solution, you would use the formula: C1V1 = C2V2. You will need 10 ml of the 50% solution (C1) and dilute it with 90 ml of water (V1) to obtain the desired 100 ml of 5% dextrose solution.
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
The pH of a 50% solution of sodium hydroxide (NaOH) and water would be around 13. Sodium hydroxide is a strong base, so when dissolved in water it will result in a highly alkaline solution with a high pH value.
You need 50 g of this drug.
The density of pure sodium hydroxide (solid) is 2,13 g/cm3.
120liters
90 ml of dextrose and 4.41 litres of water.
To prepare a 50 percent saturated solution, first determine the solute's solubility in the solvent at the given temperature. For example, if the solute's solubility is 100 grams per 100 mL of solvent, you would dissolve 50 grams of the solute in 100 mL of the solvent. Stir the mixture until the solute is fully dissolved, and if needed, adjust the volume of the solution to ensure it remains at 100 mL. Always label the solution with the concentration and date prepared.