If you mean 5H2 , that is five molar ratios of hydrogen , then '5' is the coefficient.
If you mean '5h^(2) (algebraic expression), then again '5' is the coefficient.
NB THe coefficient is the 'big' number to the left of the letters.
NNB If the 'h' refers to 'hydrogen', then it is written as a CAPITAL 'H'.
2hcl
The balanced equation should be 2Al + 6HCl -> 2AlCl3 + 3H2. Therefore, the coefficient of HCl is 6.
The chemical reaction is:SO2 + 2 H2 = 2 H2O + S
2K(s) + 2H2O(l) = 2KOH(aq) + H2(g) The eq'n is balanced. The coefficients ( molar ratios) in order of the reation eq'n are 2:2:::2:1
To balance the equation CH4 + H2O → H2 + CO, you need to change the coefficients. Start by balancing the carbon atoms - there is 1 carbon on each side so you can leave that as is. Next, balance the hydrogen atoms by adding a coefficient of 2 in front of H2 on the product side. Lastly, balance the oxygen atoms by adding a coefficient of 1 in front of H2O on the reactant side to give you CH4 + H2O → 2H2 + CO.
1.What number represents the coeffcient 5H2? 2.What does the corffcient 5H2?
2hcl
To balance the equation Ag + H2S → Ag2S + H2, you need to make sure that the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 2 in front of Ag and Ag2S to balance the silver atoms. Then, balance the hydrogen atoms by adding a coefficient of 2 in front of H2. Finally, balance the sulfur atoms by adding a coefficient of 2 in front of H2S. The balanced equation is 2Ag + 2H2S → Ag2S + H2.
To balance the reaction HBr + B → BBr3 + H2, we consider the number of atoms of each element on both sides. The balanced reaction is 6 HBr + 2 B → 2 BBr3 + 3 H2. Thus, the two substances that would have a coefficient of 2 in the balanced equation are BBr3 and H2.
2Si +2HF-2siF + 2H
The balanced equation should be 2Al + 6HCl -> 2AlCl3 + 3H2. Therefore, the coefficient of HCl is 6.
The chemical reaction is:SO2 + 2 H2 = 2 H2O + S
2K(s) + 2H2O(l) = 2KOH(aq) + H2(g) The eq'n is balanced. The coefficients ( molar ratios) in order of the reation eq'n are 2:2:::2:1
To balance the equation CH4 + H2O → H2 + CO, you need to change the coefficients. Start by balancing the carbon atoms - there is 1 carbon on each side so you can leave that as is. Next, balance the hydrogen atoms by adding a coefficient of 2 in front of H2 on the product side. Lastly, balance the oxygen atoms by adding a coefficient of 1 in front of H2O on the reactant side to give you CH4 + H2O → 2H2 + CO.
Five molecules of hydrogen have 10 atoms.
The coefficient in a chemical formula is the large number before each of the reactants or products. In the balanced equation for the synthesis of water: 2 H2 + O2 --> 2 H2O The number 2 in front of the H on both sides of the arrow are the coefficients.
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.