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A 1.0-kg mass mA and a 6.5-kg mass mB are attached to a lightweight cord that passes over a frictionless pulley. The hanging masses are free to move. Find the acceleration of the larger mass.?
Wiki User
∙ 15y ago
The acceleration will be a sum of influences of Mb weight and weight of Ma opposing it.
Pnet = Pb - Pa
anet = (Mb*g-Ma*g)/Mb
assuming g of 9.81 m/s2:
anet = 8.30 m/s2.
Wiki User
∙ 15y ago
Wiki User
∙ 12y agoFirst we say that the system is moving in the direction of the heavier object which is mB. Then we use Newton's Second Law of Motion which states that the sum of all the forces must equal the total mass of the system multiplied by the acceleration of the system (F=ma). The force acting in the direction of motion is only the weight of mB whereas the force acting against motion is the weight of mA. Tension is not included because tension is the same along the lightweight cord and therefore cancels out.
This leads to the equation:
6.5g-1.0g=(6.5 + 1.0) a where g equals 9.8m/s2
5.5g/(7.5)=a
7.2m/s2 is approximately equal to the acceleration of the system and therefore is also equal to the acceleration of the larger mass.
however since they are moving in a downward direction you must add a negative sign infront of the answer which would make the real answer -7.2m/s2
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