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A mixture of gases collected over water at 14 degree celsius has a total pressure of 0.981 ATM and occupies 55 ml How many grams of water escaped into the vapor state?
Wiki User
∙ 14y ago
T= 14+273= 287 K
P=0.981atm
V=55ml=0.055l
r=constant 0.08206
n= pv/rt (0.981x0.0551)/(0.08206x287)=0.00291mol
0.00291mol H2Ox(18.02g H2O/1mol H2O)=0.04128g H2O
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∙ 14y ago
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