37.1L is the answer
The pressure is 39,8 torr.
I believe u mean mL, m is not a unit of volume
I got 321.6mL. You use PV=nRT to find n, and plug that into PV=nRT with the new conditions to find the new volume.
Begin with the Equation; P1V1/ T1 = P2V2/ T2 Therefore, (785 torr)(2.00 L) / (37.0 C) = (X)(3.24 L)/ (58.0 C) = 759.59 TORR. To get the answer into ATM, you need to divide the answer in torr by 760. EX. 760torr = 1 atm. 759.59 torr / 760 torr = .999 atm.
Boyle's law states that pressure is indirectly proportional to the volume. There fore as the pressure of a gas at 760 torr is changed to 380 torr, the volume will increase. Boyle's Law: P1 x V1 = P2 x V2 Rearranging leads to: P1 / P2 = V2 / V1 Substituting our values: 760 / 380 = V2 / V1 Thus the final volume will be twice the initial volume.
1300<--- torr
1100
1100
P1V1 = P2V2 (740 torr)(500 ml) = (780 torr)V2 V2 = (740 torr)(500 ml) / (780 torr) V2 ~ 474 ml
The pressure is 39,8 torr.
P1*V1 = P2*V2, Therefore your numerical answer would be 100*810/72 torr.
I believe u mean mL, m is not a unit of volume
I got 321.6mL. You use PV=nRT to find n, and plug that into PV=nRT with the new conditions to find the new volume.
Begin with the Equation; P1V1/ T1 = P2V2/ T2 Therefore, (785 torr)(2.00 L) / (37.0 C) = (X)(3.24 L)/ (58.0 C) = 759.59 TORR. To get the answer into ATM, you need to divide the answer in torr by 760. EX. 760torr = 1 atm. 759.59 torr / 760 torr = .999 atm.
Using PV=nRT, 10.0ºC = 283.15ºK, R = 62.36 L torr/mol K V= (nRT)/P V = (2.35m*(62.36 L torr/mol K)*283.15ºK)/766.7 Torr V = 54.12 L
Boyle's law states that pressure is indirectly proportional to the volume. There fore as the pressure of a gas at 760 torr is changed to 380 torr, the volume will increase. Boyle's Law: P1 x V1 = P2 x V2 Rearranging leads to: P1 / P2 = V2 / V1 Substituting our values: 760 / 380 = V2 / V1 Thus the final volume will be twice the initial volume.
140 torr