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M1 and v1 --> KCN

M2 and v2 --> HClO

------SO,

M1 * v1=M2 * v2

0.36 * 0.037L=M2 * 0.075L

0.013=M2 * 0.075

M2=0.013/0.075

M2=0.17 M

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Q: A volume of 37 ml of 0.36 m kcn neutralizes a 75 ml sample of hclo solution what is the concentration of hclo?
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