2k2CrO4 + 2HCl --> k2CrO7 + 2KCl + H2O
I'm not sure abut the K2CrO4, but adding concentrated HCl to saturated NH4Cl you can form usually a white precipitate (with clearish suspension).
S sulfur
HCl (Hydrochloric acid) reacts with sodium hydroxide to produce sodium chloride (salt) and water.
KCrO4 does not exist it is K2CrO4 and is called Potassium Chromate. Potassium dichromate is K2Cr2O7
It is a chemical change. NaCl + H2O
I'm not sure abut the K2CrO4, but adding concentrated HCl to saturated NH4Cl you can form usually a white precipitate (with clearish suspension).
S sulfur
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
HCl (Hydrochloric acid) reacts with sodium hydroxide to produce sodium chloride (salt) and water.
inorganic
Take specific volume of 3N solution and increase the volume three times by adding distilled water.
KCrO4 does not exist it is K2CrO4 and is called Potassium Chromate. Potassium dichromate is K2Cr2O7
Adding hydrogen chloride to water the pH decrease.
It is a chemical change. NaCl + H2O
in benzoylation of amine, HCl is produced which by adding NaOH, HCl consumed and the raction proceed for production of further benzoylation product.
Yes, it is possible to prepare oxalic acid by adding hcl to a solution og sodum oxalate. The balance equation would be C2O4Na2 + 2HCl -----> 2NaCl + C2O4H2.
Formula: K2CrO4