The balanced equation for the decomposition of aluminum oxide is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
The balanced chemical equation for this reaction is 2Al2O3 + 3C --> 4Al + 3CO2.
The balanced equation for the reaction between aluminum and iron (III) oxide to form aluminum oxide and iron is: 2Al + Fe2O3 → Al2O3 + 2Fe
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO → 3Cu + Al2O3. This reaction produces copper and aluminum oxide.
The balanced equation for the reaction between aluminum and copper oxide is: 2Al + 3CuO -> 3Cu + Al2O3.
The balanced equation for aluminum reacting with iron(II) oxide to produce aluminum oxide and iron is: 2Al + FeO -> Al2O3 + 2Fe.
The balanced chemical equation for this reaction is 2Al2O3 + 3C --> 4Al + 3CO2.
The balanced equation for the reaction between aluminum and iron (III) oxide to form aluminum oxide and iron is: 2Al + Fe2O3 → Al2O3 + 2Fe
Aluminium + Oxygen = Aluminium Oxide 2 Al + O2 = 2AlO2
The balanced chemical equation for the reaction between calcium oxide (CaO) and aluminum (Al) to form aluminum oxide (Al2O3) and calcium (Ca) is: 2CaO + 2Al -> Al2O3 + 2Ca
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
When aluminum oxide decomposes, it produces 2 moles of aluminum and 3 moles of oxygen for every mole of aluminum oxide. Therefore, for 26.5 moles of aluminum oxide decomposed, 3 * 26.5 = 79.5 moles of oxygen are produced.
The reaction between aluminum and oxygen forms aluminum oxide. The balanced chemical equation for this reaction is 4Al + 3O2 → 2Al2O3.
Balanced equation of nitric oxide is no3 2-
This reaction is:Al + Fe2O3 = Al2O3 + Fe