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What is the number of electrons if an isotope has an atomic number of 51 and a mass number of 123?

51: For a neutral atom, the number of electrons always is the same as the number of protons, which in turn is the atomic number. The mass number is irrelevant to this question.


How many protons and neutrons does tellurium-123 have?

Tellurium-123 has 52 protons and 71 neutrons.


What does 123 stand for in 123 Nuclear Agreement?

Section 123 of the US atomic energy act


What is the isotope iodine 75?

There is no such isotope (75) known. Iodine (atom number 53, average atomic mass 127) has 53 protons and 70 up till 82 neutrons. The lowest known isotope number therefor is 123.


The India us nuclear deal is called 123 agrement what does 123 denote?

Section 123 of US Atomic energy act


Which is not Fibonacci number 89 or 123?

123 is not a Fibonacci number.


123 is a number?

yes, 123 is a number it is the first 3 numbers


What is half of the number 246?

123


How many neutrons are in the nucleus of an atom of 118 50 Sn?

Sn (tin) has an atomic number of 50, which indicates there are 50 protons in its nucleus. If the atomic mass is 118, then the number of neutrons is the difference between the two numbers, or 68 neutrons.


What number is divisible by 9 123 234 or 345?

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123 is not an unlucky number in Ireland.


How do you calculate percent abundance for antimony?

The atomic mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%