The Atomic Mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%
Each isotope's mass is multiplied by its percent abundance to account for the contribution of each isotope to the overall average atomic mass of an element. This calculation ensures that the final average atomic mass reflects the weighted average of the masses of all isotopes based on their abundance in nature.
The natural percent abundance of the heavier isotope of gallium, gallium-71, is approximately 39.892%.
Sb is the chemical symbol of antimony (stibium).
Antimony-121 at 57.25%, the rest is Antimony-123
Antimony is in period 5
Antimony has two stable isotopes: antimony-121 and antimony-123. Antimony-121 has a higher natural abundance at approximately 57.2%, while antimony-123 makes up the remaining abundance at around 42.8%.
You calculate the total amount of whatever it is that you want to find the silicon abundance for. Then you calculate the amount f silicon in that. Then percentage abundance of silicon = 100*amount of silicon/total amount Typically the amount would be measured as the mass.
The fractional abundance is calculated by dividing the abundance of the isotope of interest by the abundance of all the isotopes of the element. For chlorine-37, the percent abundance is 0.2434, or 24.34%.
after inspection of fabric based on 4 point system how to calculate the % of fabric pass or fail
The percent abundance of boron is approximately 19.78% for ^10B and 80.22% for ^11B.
To calculate the relative abundance of two isotopes, you would divide the abundance of one isotope by the total abundance of both isotopes and then multiply by 100 to get a percentage.
Each isotope's mass is multiplied by its percent abundance to account for the contribution of each isotope to the overall average atomic mass of an element. This calculation ensures that the final average atomic mass reflects the weighted average of the masses of all isotopes based on their abundance in nature.
the result is 1.00, because relative abundance is just the percent abundance in decimal form. The percent abundance sum is 100%, therefore the answer is 1.00 because the decimal of 100% is 1.00
Take percent abundance times atomic mass for each isotope then add all up for average atomic mass.
The natural percent abundance of the heavier isotope of gallium, gallium-71, is approximately 39.892%.
It accounts ofr 0.934% by volume, of the earth's atmosphere.
To calculate the abundance of boron isotopes, you would typically need to know the masses and natural abundances of each isotope. You can then use these values to calculate a weighted average, taking into account the abundance of each isotope relative to its mass. The formula for calculating isotopic abundance involves multiplying the natural abundance of each isotope by its mass and then summing these values for all isotopes.