Fe2(SO4)3
The chemical formula is Fe2(SO4)3 (anhydrous).
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
Iron(III) Sulfate = Fe2(SO4)3
Iron(III) Sulfate = Fe2(SO4)3
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
The chemical formula is Fe2(SO4)3 (anhydrous).
To find the mass of 1.40 mol of iron (III) sulfate (Fe2(SO4)3), you need to calculate the molar mass of the compound. Iron (III) sulfate has a molar mass of approximately 399.9 g/mol. Therefore, the mass of 1.40 mol of iron (III) sulfate would be 1.40 mol x 399.9 g/mol = 559.86 grams.
Iron(III) Sulfate = Fe2(SO4)3
Iron(III) Sulfate = Fe2(SO4)3
In iron (III) sulfate, the ratio of iron to sulfate ions is 1:2. This means that for every one mole of iron (III) sulfate, there are three moles of sulfate ions. To find the number of sulfate ions in a 375.0 gram sample of iron (III) sulfate, you would first calculate the number of moles of iron (III) sulfate, and then multiply that by three to find the number of sulfate ions.
The systematic name for the compound Fe2(SO4)3 is iron(III) sulfate. In this compound, the iron ion has a +3 charge, hence denoted as iron(III), and sulfate is a polyatomic ion with a -2 charge, requiring three sulfate ions to balance the charge of two iron ions.
Iron (III) Sulfide Ferrous Sulfide
The chemical formula for iron (III) sulfate is Fe2(SO4)3.
The chemical formula for iron (III) sulfate is Fe2(SO4)3. It consists of two iron (III) ions and three sulfate ions.
Fe(SO4)3 is Iron(III) sulfate Wrong: Fe2(SO4)3 is iron(III) sulfate.
The products of the reaction between sodium hydroxide and iron(III) sulfate are iron(III) hydroxide and sodium sulfate. This reaction forms a precipitate of iron(III) hydroxide while sodium sulfate remains in solution.
in hydrated form it is soluble but in anhydrous form it is insoluble