The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
To calculate the amount of oxygen needed to oxidize iron, we need to use the stoichiometry of the reaction. The equation for the reaction of iron with oxygen to form iron(III) oxide is: 4 Fe + 3 O2 -> 2 Fe2O3. This shows that 3 mol of O2 are required to react with 4 mol of Fe. So, we first need to calculate the number of moles of Fe in 140 g of Iron, then use the stoichiometry to determine the number of moles of O2 needed. The molar mass of Iron(III) oxide (Fe2O3) is 159.69 g/mol.
The molar mass of carbon is 12.01 g/mol. To find the mass of 0.5 mol of carbon atoms, you would multiply the molar mass (12.01 g/mol) by the number of moles (0.5 mol) to get the answer, which is 6.005 grams.
To find the mass of carbon in C2H6, we first need to calculate the molar mass of C2H6. Carbon has a molar mass of 12 g/mol, and hydrogen has a molar mass of 1 g/mol. The molar mass of C2H6 is (212) + (61) = 30 g/mol. The mass of carbon in 350 grams of C2H6 is then (2*12)/30 * 350 = 140 grams.
To calculate the number of moles in 140 g of Cl2, divide the given mass by the molar mass of Cl2. Number of moles = Mass / Molar mass = 140 g / 70.9 g/mol = 1.97 moles. Therefore, there are 1.97 moles of chlorine gas in 140 g of Cl2.
To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.
Milliliters can't be converted to grams. Milliliters measure volume, while grams measure mass.
The mass of an aluminum can typically ranges from about 12 to 15 grams, depending on the design and size. If we take an average mass of approximately 14 grams per can, the total mass for 10 aluminum cans would be around 140 grams. Thus, the mass average for 10 aluminum cans is approximately 140 grams.
4.23 - 4.93 ounces mass
140 ml of water is approximately 140 grams
Grams can't be converted to milliliters. Grams measure mass, while milliliters measure volume.
140 grams of feathers
140 pounds = 6.35 x 104 grams.
There are 140 grams, or about 4.938 ounces.
A mole of a substance contain 6,022 140 857.10ex23 (number of Avogadro - NA ) molecules.A mass (in grams) contain a number of molecules equal to:(given mass x number of Avogadro)/molar mass
140 ml of water is 140 grams,- other materials will differ.
To calculate the amount of oxygen needed to oxidize iron, we need to use the stoichiometry of the reaction. The equation for the reaction of iron with oxygen to form iron(III) oxide is: 4 Fe + 3 O2 -> 2 Fe2O3. This shows that 3 mol of O2 are required to react with 4 mol of Fe. So, we first need to calculate the number of moles of Fe in 140 g of Iron, then use the stoichiometry to determine the number of moles of O2 needed. The molar mass of Iron(III) oxide (Fe2O3) is 159.69 g/mol.
140 grams = 5 ounces of lentils (or more precisely 4.93835467 ounces)