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Start by writing two half reactions. Next, balance the main element. Then balance the oxygens by adding water to the appropriate side. Next balance the hydrogens by adding H+ to the appropriate side. Next balance the charge by adding electrons to the appropriate side. Then combine the two half reactions in such a way that the electrons cancel. If you are in a basic solution, you then add hydroxide ions to both sides of the equation, converting the H+ ions into H2O. For example, if you are given the skeleton equation

Fe(2+) + Cr2O7(2-) --> Fe(3+) + Cr(3+) , start by writing two half reactions:

Fe (2+)--> Fe(3+)

Cr2O7(2-) --> Cr(3+)

Then balance the main element in each half reaction:

Fe(2+)-->Fe(3+)

Cr2O7(2-)-->2Cr(3+)

Next balance the oxygens in each half reaction:

Fe(2+)--> Fe(3+)

Cr2O7(2-) --> 2Cr(3+) + 7H2O

Now balance the hydrogens in each half reaction:

Fe(2+)--> Fe(3+)

Cr2O7(2-) + 14H+ --> 2Cr(3+) + 7H2O

Now balance the charge in each half reaction:

Fe(2+) --> Fe(3+) + e(-)

Cr2O7(2-) + 14H+ +6e(-) --> 2Cr(3+) + 7H2O

Now you want to combine the equations and cancel the electrons, so you multiply the first equation by six and add the equations together:

6Fe(2+) + Cr2O7(2-) + 14H+ +6e(-) --> 6Fe(3+) + 6e(-) + 2Cr(3+) + 7H2O, which is the same as 6Fe(2+) + Cr2O7(2-) + 14H+ --> 6Fe(3+) + 2Cr(3+) + 7H2O.

If you are in acidic solution, you are now done. If you are in basic solution, you need to deal with the H+ ions by adding hydroxide to both sides of the equation.

6Fe(2+) + Cr2O7(2-) + 14H+ + 14OH- --> 6Fe(3+) + 2Cr(3+) + 7H2O + 14OH-, which is 6Fe(2+) + Cr2O7(2-) + 14H2O --> 6Fe(3+) + 2Cr(3+) + 7H2O + 14OH-, or

6Fe(2+) + Cr2O7(2-) + 7H2O --> 6Fe(3+) + 2Cr(3+) + 14OH-

Voila, you're done!

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