For complete combustion, the equation is C + O2 => CO2. If the supply of oxygen is limited, carbon monoxide can also form, along with soot and other materials.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The balanced equation for ethanol (C2H5OH) burned in air is: C2H5OH + 3O2 -> 2CO2 + 3H2O. This equation shows that ethanol reacts with oxygen to produce carbon dioxide and water.
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
The equation is CS2 + 3 O2 -> CO2 + 2 SO2.
octane + oxygen --> water + carbon dioxide
The balanced chemical equation for burning C18H38 in air is: 2C18H38 + 55O2 → 36CO2 + 38H2O
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
The balanced equation for ethanol (C2H5OH) burned in air is: C2H5OH + 3O2 -> 2CO2 + 3H2O. This equation shows that ethanol reacts with oxygen to produce carbon dioxide and water.
The word equation for a candle burning in the air is: Wax + Oxygen → Carbon Dioxide + Water + Light + Heat.
If there is an excess of air, the reaction should produce diphosphorus pentoxide as its only product. If additionally the phosphorus molecule is simply a phosphorus atom, the balanced equation is: 4 P + 5 O2 -> 2P2O5. If phosphorus is considered to form a tetraatomic molecule, the equation would be: P4 + 5 O2 -> 2 P2O5
For coal is carbon burning:C + O2 = CO2
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
The equation is CS2 + 3 O2 -> CO2 + 2 SO2.
Cs2 + 3 o2 → co2 + 2 so2
ethanol + oxygen ----> Carbon Dioxide + water (assume complete combustion) CH3CH2OH + 3O2 ---> 2CO2 + 3H2O *also, when a compound is burning,we chemists use the term Combustion, which refers to the exothermic reactions which occur between some fuel source and an oxidant. Thus, "Ethanol burning in air" is rather redundant :]
octane + oxygen --> water + carbon dioxide